PHP sprintf转义％

Question

我想要以下输出：

将从您的充值帐户中扣除27.59欧元的50％。

当我做这样的事情时：

$variablesArray[0] = '€';
$variablesArray[1] = 27.59;
$stringWithVariables = 'About to deduct 50% of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);

但这给了我这个错误，vsprintf() [function.vsprintf]: Too few arguments in ...因为它也考虑使用%in 50%进行替换。我该如何逃脱？

Answer 1

与另一个转义%：

$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';