AngularJS过滤嵌套对象

Question

我有这样的角度嵌套对象。有没有办法为嵌套属性过滤它

<li ng-repeat="shop in shops | filter:search">
search.locations.city_id = 22

我只显示父元素，但想按两个元素进行过滤，例如：

search = 
  category_id: 2
  locations:
    city_id: 368

[
 name: "xxx"
 category_id: 1
 locations: [
   city_id: 368
   region_id: 4
  ,
   city_id: 368
   region_id: 4
  ,
   city_id: 368
   region_id: 4
  ]
,
 name: "xxx"
 category_id: 2
 locations: [
   city_id: 30
   region_id: 4
  ,
   city_id: 22
   region_id: 2
  ]
]

Answer 1

是的，如果我正确理解您的示例，则可以。

根据集合的大小，计算迭代所用的集合可能会更好，ng-repeat这样过滤器就不会随着模型的更改而不断地进行操作。

http://jsfiddle.net/suCWn/

基本上，如果我理解正确，您会执行以下操作：

$scope.search = function (shop) {

    if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
        return true;
    }

    var found = false;
    angular.forEach(shop.locations, function (location) {          
        if (location.city_id === parseInt($scope.selectedCityId)) {
            found = true;
        }
    });

    return found;
};