int ispunct（int c）

描述 (Description)

C库函数int ispunct(int c)检查传递的字符是否是标点字符。 标点符号是任何不是字母数字的图形字符（如isgraph中所示）（如isalnum中所示）。

声明 (Declaration)

以下是ispunct（）函数的声明。

int ispunct(int c);

参数 (Parameters)

• c - 这是要检查的字符。

返回值 (Return Value)

如果c是标点符号else，则此函数返回非零值（true），为零（false）。

例子 (Example)

以下示例显示了ispunct（）函数的用法。

#include <stdio.h>
#include <ctype.h>
int main () {
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';
   if( ispunct(var1) ) {
      printf("var1 = |%c| is a punctuation character\n", var1 );
   } else {
      printf("var1 = |%c| is not a punctuation character\n", var1 );
   }
   if( ispunct(var2) ) {
      printf("var2 = |%c| is a punctuation character\n", var2 );
   } else {
      printf("var2 = |%c| is not a punctuation character\n", var2 );
   }
   if( ispunct(var3) ) {
      printf("var3 = |%c| is a punctuation character\n", var3 );
   } else {
      printf("var3 = |%c| is not a punctuation character\n", var3 );
   }
   if( ispunct(var4) ) {
      printf("var4 = |%c| is a punctuation character\n", var4 );
   } else {
      printf("var4 = |%c| is not a punctuation character\n", var4 );
   }
   return(0);
}   

让我们编译并运行上面的程序，它将产生以下结果 -

var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character