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has 是否存在

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2023-12-01

has

确定数据是否存在

has($table, $where)
  • table [string]

    表名.

  • where [array]

    WHERE 条件.

has($table, $join, $where)
  • table [string]

    表名.

  • join [array]

    多表查询.

  • where [array]

    WHERE条件.

Return: [boolean] 返回 TRUE 或者 FALSE.可用于做密码判断。
if ($database->has("account", [    "AND" => [        "OR" => [            "user_name" => "foo",            "email" => "foo"        ],        "password" => "12345"    ]])){    echo "Password is correct.";}else{    echo "Password error.";}