android节日接口,节假日api及其整合
节假日api
今天项目中有一个需求需要用到节假日，项目需求是
要有调休日
要有周末
于是就去网上找。
看到比较合适的大概就这几个：
1.http://tool.bitefu.net/jiari?d=2018
返回数据：
返回结果：
{
"2018": {
"1001": "2",
"1002": "2",
"1003": "2",
"1004": "1",
"1005": "1",
"1006": "1",
"1007": "1",
"0101": "2",
"0215": "1",
"0216": "2",
"0217": "2",
"0218": "2",
"0219": "1",
"0220": "1",
"0221": "1",
"0405": "2",
"0406": "1",
"0407": "1",
"0429": "1",
"0430": "1",
"0501": "2",
"0616": "1",
"0617": "1",
"0618": "2",
"0922": "1",
"0923": "1",
"0924": "2"
}
}
优点是可以一次性获取全年的。缺点是只有节假日，没有周末，没有调休
{
"201801": {
"13": "1",
"14": "1",
"20": "1",
"21": "1",
"27": "1",
"28": "1",
"01": "2",
"06": "1",
"07": "1"
}
优点是有周末，缺点是没有调休
{
"code": 10000,
"data": 2
}
优点是可以区分周末，节假日，工作日。缺点是API太过简陋，只能针对某一天进行查询。
综合比较，打算用第三个api来进行查询，利用调休日一般都是周末的规律，如果是周末并且是工作日那一定是调休。基于此生成一个节假日，调休日，工作日都有区分的json文件。
Python代码附带如下：
import requests
import re
import json
import time
import datetime
import random
startday = [2016, 1, 1]
num = 1096 # 开始天之后的多少天,这里设为3年
workdays = 5 # 开始天是星期几. 这里周日为0，周一到周六分别为1-6
def getHoliday(start, index, days):
daylist = [] # 记录下所有的调休日0，法定节假日2，和周末3
startday = datetime.date(start[0], start[1], start[2])
for i in range(0 , days):
workindex = (index + i) % 7
rawDate = startday + datetime.timedelta(days = i)
regex=re.compile(r'\d\d')
tmpDate = regex.findall(str(rawDate))
date = str(tmpDate[0]) + str(tmpDate[1]) + str(tmpDate[2]) + str(tmpDate[3])
r = requests.get(r'http://api.goseek.cn/Tools/holiday?date=' + date)
r.encoding = r.apparent_encoding
json_data = json.loads(r.text)
if int(json_data['data']) == 0:
if workindex == 0 or workindex == 6:
daylist.append({"date":str(rawDate), "val":0})
elif int(json_data['data']) == 1:
daylist.append({"date":str(rawDate), "val":3})
elif int(json_data['data']) == 2:
daylist.append({"date":str(rawDate), "val":2})
return daylist
def buildJson(daylist):
date_1 = {"date": daylist}
date_2 = {"date": date_1, "version": 1}
with open('yourfile.json', 'w') as holiday:
json.dump(date_2, holiday)
print("写出完成")
daylist = getHoliday(startday, workdays, num)
buildJson(daylist)