Description:
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a"
maps to ".-"
, "b"
maps to "-..."
, "c"
maps to "-.-."
, and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-.-....-", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
Example: Input: words = ["gin", "zen", "gig", "msg"] Output: 2 Explanation: The transformation of each word is: "gin" -> "--...-." "zen" -> "--...-." "gig" -> "--...--." "msg" -> "--...--." There are 2 different transformations, "--...-." and "--...--.".
Note:
words
will be at most 100
.words[i]
will have length in range [1, 12]
.words[i]
will only consist of lowercase letters.Solution 1:
class Solution {
public:
int uniqueMorseRepresentations(vector<string>& words) {
const vector<string> letters = { ".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.." };
set<string> str_set;
string s;
for (const auto &word : words) {
s = "";
for (const auto &ch : word) {
s.append(letters[ch-'a']);
}
str_set.insert(s);
}
return str_set.size();
}
};
Solution 2:
class Solution {
public:
int uniqueMorseRepresentations(vector<string>& words) {
const vector<string> letters = { ".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.." };
int count = 0;
set<string> temp;
string s;
for (int i = 0; i<words.size(); i++)
{
for (int j = 0; j<words[i].size(); j++)
{
s.append(letters[(words[i])[j] - 'a']);
}
temp.insert(s);
s = "";
}
count = temp.size();
return count;
}
};
Solution 3:
class Solution {
public:
int uniqueMorseRepresentations(vector<string>& words) {
string ws[] = {".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
set<string> a;
for(string n:words){
string t="";
for(int i=0;i<n.size();i++){
string tn = ws[(int)(n[i])-97];
t+=tn;
}
a.insert(t);
}
return a.size();
}
};