[leetcode] 1333. Filter Restaurants by Vegan-Friendly, Price and Distance
Description
Given the array restaurants where restaurants[i] = [idi, ratingi, veganFriendlyi, pricei, distancei]. You have to filter the restaurants using three filters.
The veganFriendly filter will be either true (meaning you should only include restaurants with veganFriendlyi set to true) or false (meaning you can include any restaurant). In addition, you have the filters maxPrice and maxDistance which are the maximum value for price and distance of restaurants you should consider respectively.
Return the array of restaurant IDs after filtering, ordered by rating from highest to lowest. For restaurants with the same rating, order them by id from highest to lowest. For simplicity veganFriendlyi and veganFriendly take value 1 when it is true, and 0 when it is false.
Example 1:
Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 1, maxPrice = 50, maxDistance = 10
Output: [3,1,5]
Explanation:
The restaurants are:
Restaurant 1 [id=1, rating=4, veganFriendly=1, price=40, distance=10]
Restaurant 2 [id=2, rating=8, veganFriendly=0, price=50, distance=5]
Restaurant 3 [id=3, rating=8, veganFriendly=1, price=30, distance=4]
Restaurant 4 [id=4, rating=10, veganFriendly=0, price=10, distance=3]
Restaurant 5 [id=5, rating=1, veganFriendly=1, price=15, distance=1]
After filter restaurants with veganFriendly = 1, maxPrice = 50 and maxDistance = 10 we have restaurant 3, restaurant 1 and restaurant 5 (ordered by rating from highest to lowest).
Example 2:
Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 0, maxPrice = 50, maxDistance = 10
Output: [4,3,2,1,5]
Explanation: The restaurants are the same as in example 1, but in this case the filter veganFriendly = 0, therefore all restaurants are considered.
Example 3:
Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 0, maxPrice = 30, maxDistance = 3
Output: [4,5]
Constraints:
- 1 <= restaurants.length <= 10^4
- restaurants[i].length == 5
- 1 <= idi, ratingi, pricei, distancei <= 10^5
- 1 <= maxPrice, maxDistance <= 10^5
- veganFriendlyi and veganFriendly are 0 or 1.
- All idi are distinct.
分析
题目的意思是：给定一个数组，数组的每个元素代表餐厅的5个属性，求满足veganFriendlyi, pricei, distancei，这三个限制条件后的元素的按照ratings倒序排序的索引输出。思路也是很直接，先把满足条件的元素找出来，然后排序一下，python用lambda表达式能够很好的实现，如果是倒序排序的话，就取负值就行了。
代码
class Solution:
def filterRestaurants(self, restaurants: List[List[int]], veganFriendly: int, maxPrice: int, maxDistance: int) -> List[int]:
rest=[]
for i,restaurant in enumerate(restaurants):
res_id,rating,vegan,price,distance=restaurant
if(veganFriendly==0 and price<=maxPrice and distance<=maxDistance):
rest.append(restaurant)
elif(veganFriendly==1 and vegan==1 and price<=maxPrice and distance<=maxDistance):
rest.append(restaurant)
res = [x[0] for x in sorted(rest, key=lambda x: (-x[1], -x[0]))]
return res