oracle中update的where条件跟select

印晋
2023-12-01
update CUST_BASIC_INFO set AgeGroup = 2 where 
    
  case
     when length(card_no) = 18 then  ---截取身份证年龄
                       ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(to_date(substr(card_no, 7, 8), 'yyyy-MM-dd'),
                                       'yyyyMMdd')) / 10000)
                when length(card_no) = 15 then
                         ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(to_date('19' || substr(card_no, 7, 6),
                                               'yyyy-MM-dd'),
                                       'yyyyMMdd')) / 10000)
                  when length(cu.card_no) != 18 and length(cu.card_no) != 15 and BIRTHDAY != null
                     then ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(BIRTHDAY,
                                       'yyyyMMdd')) / 10000)
                       
                     end 
 
 
  in (select cu1.cuage from (select ---截取身份证年龄
  case
     when length(cu.card_no) = 18 then
                       ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(to_date(substr(cu.card_no, 7, 8), 'yyyy-MM-dd'),
                                       'yyyyMMdd')) / 10000)
                when length(cu.card_no) = 15 then
                         ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(to_date('19' || substr(cu.card_no, 7, 6),
                                               'yyyy-MM-dd'),
                                       'yyyyMMdd')) / 10000)
                                       
                   when length(cu.card_no) != 18 and length(cu.card_no) != 15 and BIRTHDAY != null
                     then ceil((to_char(sysdate, 'yyyyMMdd') -
                              to_char(BIRTHDAY,
                                       'yyyyMMdd')) / 10000)
                       
                     end as cuAge

 from cust_basic_info cu)cu1 where cu1.cuage>=17 and cu1.cuage<=24) 

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