python args_Python request.args方法代码示例

燕宏胜
2023-12-01
")

args = dict(request.args)

for nl in nlist:

args['n'] = nl

argstr = urlencode(sorted(args.items()), doseq=True)

result.append("follow {1}
".format(argstr, nl))

result.append("

 类似资料: