链接:https://leetcode.com/problems/triangle/description/
Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11
(i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
class Solution {
public:
int minimumTotal(vector<vector<int>>& triangle) {
int size = triangle.size();
std::vector<int > dp;
dp.resize(size);
for (int j = 0; j < size; j++) dp[j] = triangle[size-1][j];
// 自底向上
for (int i = size-2; i >= 0; i--) {
for (int j = 0; j <= i; j++) {
dp[j] = min(dp[j], dp[j+1])+triangle[i][j];
}
}
return dp[0];
}
};
思路:这道题的动态规划思想是自底向上的。之前用了自顶向下的方法来解,但是实在不好做。以后思考这类问题要学会换角度进行思考。