C语言实现矩阵翻转(上下翻转、左右翻转)

C语言实现矩阵翻转 上下翻转与左右翻转

实例代码：

#include <stdio.h> 
  
void matrix (int m, int n, int t) 
{ 
  int arr[m][n]; 
  int i, j, k; 
  
  for (i = 0; i < m; i++){ 
    for (j = 0; j < n; j++){ 
      scanf("%d", &arr[i][j]); 
    } 
  } 
  if (t == 0){//左右翻转 
      for (i = 0; i < m; i++){ 
        for (j = n-1; j >= 0; j--){ 
          if ( j == 0 ) { 
            printf("%d", arr[i][j]); 
          } 
          else { 
            printf("%d ", arr[i][j]); 
          } 
        } 
        printf("\n"); 
      } 
  } 
  else if (t == 1){//上下翻转 
    for (i = m-1; i >= 0; i--){ 
      for (j = 0; j < n; j++){ 
        if ( j == n - 1 ) { 
          printf("%d", arr[i][j]); 
        } 
        else { 
          printf("%d ", arr[i][j]); 
        } 
      } 
      printf("\n"); 
    } 
  } 
} 
  
int main() 
{ 
  int m, n, t; 
  
  scanf("%d %d %d", &m, &n, &t); 
  matrix (m, n, t); 
  
  return 0; 
} 

 动态分配内存

void matrix (int m, int n, int t) 
{ 
  int i, j; 
  int **arr=(int**)malloc(m*sizeof(int*)); 
  for(i = 0; i < m; i++) 
  { 
    arr[i] = (int*)malloc(n * sizeof(int)); 
    for(j = 0; j < n;j++) 
    { 
      scanf("%d", &arr[i][j]); 
    } 
  } 
  /* 
  int **arr = new int*[m]; 
  for(i=0;i<m;i++) 
  { 
    arr[i] = new int[n]; 
    for(j=0;j<n;j++) 
    { 
      scanf("%d", &arr[i][j]); 
    } 
  } 
  */ 
  if (t == 0){//左右翻转 
      for (i = 0; i < m; i++){ 
        for (j = n-1; j >= 0; j--){ 
          if ( j == 0 ) { 
            printf("%d", arr[i][j]); 
          } 
          else { 
            printf("%d ", arr[i][j]); 
          } 
        } 
        printf("\n"); 
      } 
  } 
  else if (t == 1){//上下翻转 
    for (i = m-1; i >= 0; i--){ 
      for (j = 0; j < n; j++){ 
        if ( j == n - 1 ) { 
          printf("%d", arr[i][j]); 
        } 
        else { 
          printf("%d ", arr[i][j]); 
        } 
      } 
      printf("\n"); 
    } 
  } 
} 

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