javascript - js怎么把数组里id相同的合并到一个对象里？

Question

原数据：
const list =[
    {
        id: "202301",
        jine: 23,
        type: "晚餐"
    },
    {
        id: "202301",
        jine: 87.5,
        type: "早餐"
    },
    {
        id: "202301",
        jine: 1065.5,
        type: "中餐"
    },
    {
        id: "202302",
        jine: 10,
        type: "晚餐"
    },
    {
        id: "202302",
        jine: 181.5,
        type: "早餐"
    },
    {
        id: "202302",
        jine: 633.5,
        type: "中餐"
    }
]
期望数据格式：
const list =[
    {
        id: "202301",
        jine1: 87.5,//早
        jine2: 1065.5,//中
        jine3: 23,//晚

    },
    {
        id: "202302",
        jine1: 181.5,//早
        jine2: 1065.5,//中
        jine3: 10,//晚
    }
]

Answer 1

const sortListById = (list) => {
    const map = {}
    list.forEach(item => {
        if (map[item.id]) {
            map[item.id].length++
            const jineName = `jine${map[item.id].length}`
            map[item.id].value[jineName] = item.jine
        } else {
            map[item.id] = { value: { id: item.id, jine1: item.jine }, length: 1 }
        }
    })
    return Object.values(map).map(item => item.value)
}

Answer 2

let obj = {}
list.forEach(item => {
    if (!obj[item.id]) {
        obj[item.id] = {id: item.id}
    }
    if (item.type === "早餐") {
        obj[item.id].jine1 = item.jine
    } else if (item.type === "中餐") {
        obj[item.id].jine2 = item.jine
    } else if (item.type === "晚餐") {
        obj[item.id].jine3 = item.jine
    }
})
const result = Object.values(obj)

Answer 3

Object.entries(Object.groupBy(list, item => item.id))
  .map(([k, v]) => ({ 
    id: k, 
    jine1: v.find(e => e.type === '早餐')?.jine, 
    jine2: v.find(e => e.type === '中餐')?.jine, 
    jine3: v.find(e => e.type === '晚餐')?.jine 
  }))