typescript - Typescript继承，子类有没有方便一点的构造器使用方法？

Question

正常父类的构造器里会用到一些单例工具类，而且这种后续还会增加。例如：

export class ClassA {    constructor(        public s1: ServiceA,        public s2: ServiceB,        public s3: ServiceC,    ) {    }}export class ClassB extends ClassA {    constructor(        public s1: ServiceA,        public s2: ServiceB,        public s3: ServiceC,    ) {        super(s1, s2, s3);    }}

子类必须调父类构造器，这种传参代码，每次复制粘贴。主要是后续增加一个参数，每个子类都得改过去。
就不能设计成子类默认就有一样的构造器，已经隐式调用了super，别让人手写

Answer 1

export class ClassA {    constructor(        public s1: ServiceA,        public s2: ServiceB,        public s3: ServiceC,    ) {    }}export class ClassB extends ClassA {    constructor(...args: ConstructorParameters<typeof ClassA>) {        super(...args);    }}

Answer 2

可以使用装饰器试试

type Constructor<T = {}> = new (...args: any[]) => T;function AutoSuper<T extends Constructor>(constructor: T) {    return class extends constructor {        constructor(...args: any[]) {            super(...args);        }    };}export class ClassA {    constructor(        public s1: number,        public s2: number,        public s3: number,    ) {    }}@AutoSuperexport class ClassB extends ClassA {}