我再react中使用zustand。我想增加命名空间,代码如下,vscode一直提示
import { create, StateCreator } from "zustand"type AboutState = { count: number increase: (n?: number) => void decrease: () => void}type HomeState = { n: number increase: (n?: number) => void decrease: () => void}type Store = { about: AboutState home: HomeState}const createAbout: StateCreator<AboutState> = (set) => { return { count: 0, increase: (n = 1) => set((state) => ({ count: state.count + n })), decrease: () => set((state) => ({ count: state.count - 1 })), }}const createHome: StateCreator<HomeState> = (set) => { return { n: 0, increase: (n = 1) => set((state) => ({ n: state.n + n })), decrease: () => set((state) => ({ n: state.n - 1 })), }}export const useStore = create<Store>()((...set) => ({ about: createAbout(...set), home: createHome(...set),}))
看着感觉你是不是想要下面这种:
type PartialSet<T> = (s: (state: T) => Partial<T>) => unknown;const createAbout = (set: PartialSet<AboutState>) => { return { count: 0, increase: (n = 1) => set((state) => ({ count: state.count + n })), decrease: () => set((state) => ({ count: state.count - 1 })), }}const createHome = (set: PartialSet<HomeState>) => { return { n: 0, increase: (n = 1) => set((state) => ({ n: state.n + n })), decrease: () => set((state) => ({ n: state.n - 1 })), }}export const useStore = create<Store>()((set) => ({ about: createAbout((innerSet) => set(state => ({ about: {...state.about, ...innerSet(state.about)} }))), home: createHome((innerSet) => set(state => ({ home: {...state.home, ...innerSet(state.home)} }))),}))// 使用方式:useStore().about.count)useStore().about.increase();
为什么using指令在包含在匿名命名空间中时表现得好像出现在全局范围?
引入Maven依赖 <dependency> <groupId>org.apache.shardingsphere</groupId> <artifactId>shardingsphere-jdbc-core-spring-namespace</artifactId> <version>${shardingsphere.version}</version> </depend
引入 Maven 依赖 <dependency> <groupId>org.apache.shardingsphere</groupId> <artifactId>shardingsphere-jdbc-core-spring-namespace</artifactId> <version>${shardingsphere.version}</version> </depe
引入Maven依赖 <dependency> <groupId>org.apache.shardingsphere</groupId> <artifactId>shardingsphere-jdbc-core-spring-namespace</artifactId> <version>${shardingsphere.version}</version> </depend
我有一个非常复杂的XML树,它在架构中有几个命名空间。我设法生成了相应的Jaxb(使用eclipse IDE),marshaller/unmarshaller工作正常。 现在,我需要将XML转换为特定格式,因为我需要将其提供给某个系统,并且我没有其他选择。 生成的XML是: 我需要生成的XML 我正在使用Jaxb RI 2.2.6 到目前为止我所做的工作:1。 并从方法返回“” > @使用xmln
我们知道命名空间: 但是什么是全局命名空间呢?