我需要数元音和辅音，但辅音[重复]让我感到困惑

Question

我不知道如何同时有元音和辅音。代码的元音部分工作正常。我不知道如何添加辅音。

import java.util.Scanner;

public class Main
{
   public static void main(String args[])
   {
      Scanner in = new Scanner(System.in);

      System.out.println("Enter some text: ");
      String str = in.nextLine();
      System.out.println(str);

System.out.print("your input has " + count_Vowels(str) + "vowels");
    }
 public static int count_Vowels(String str)
    {
        int vcount = 0;
        for (int i = 0; i < str.length(); i++)
        {
            char ch = str.charAt(i);
            if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u')
            {
              vcount++;
            }
        }
        return vcount;
    }
public static int count_Consanants(String str)
    {
      int ccount = 0;
      for (int i = 0; i < str.length(); i++)
    {
      char ch = str.charAt(i);
      if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u')
      {
        vcount++;
      }
      else
      {
        consonants++;
      }
    }
  }  
}

我似乎无法理解代码的辅音部分

Answer 1

这里有一种方法。

• 首先，它将字符串转换为小写，以便于搜索

Scanner in = new Scanner(System.in);

System.out.println("Enter some text: ");
String str = in.nextLine().toLowerCase();
String vowels = "aeiou";
System.out.println(str);

int vcount = 0;
int ccount = 0;

for (char c : str.toCharArray()) {
    if (Character.isLetter(c)) {
        if (vowels.indexOf(c) >= 0) {
            vcount++;
        } else {
            // must be a consonant
            ccount++;
        }
    }
}
System.out.printf("There were %d vowels and %d consonants%n",
        vcount, ccount);

Answer 2

您的代码还将计算非辅音的其他字符。以下是计算元音和辅音的简单方法：

for (int i = 0; i < str.length(); i++) {    
    //Checks whether a character is a vowel
    if (str.charAt(i) == 'a' || str.charAt(i) == 'e' || str.charAt(i) == 'i' || str.charAt(i) == 'o' || str.charAt(i) == 'u') {      
        vCount++;    
    }    
    //Checks whether a character is a consonant    
    else if (str.charAt(i) >= 'a' && str.charAt(i)<='z') {        
        cCount++;    
    }    
}    

同样，您也可以修改大写字符的代码。

略显优雅：

Set<Character> vowels = new HashSet<>(Arrays.asList('a', 'e', 'i', 'o', 'u'));

for (int i = 0; i < str.length(); i++) {
    char c = str.charAt(i);
    if (vowels.contains(c)) {
        vCount++;
    } else if (c >= 'a' && c <= 'z') {
        cCount++;
    }
}