如何使用quarkus反应式mysql客户端和mutiny api在mysql中插入和获取上次插入的id

Question

我将如何创建事务、插入行、提交事务并获取最后插入的id。所以该方法应该返回一个Uni

return this.client.begin()
   .flatMap(tx -> tx
           .preparedQuery("INSERT INTO person (firstname,lastname) VALUES ($1,$2)")
           .execute(Tuple.of(person.getFirstName(),person.getLastName()))
           .onItem().produceUni(id-> tx.query("SELECT LAST_INSERT_ID()"))
           .onItem().produceUni(res -> tx.commit())
           .onFailure().recoverWithUni(ex-> tx.rollback())
   );




Answer 1

尝试以下操作：

return client.begin().onItem().produceUni(tx -> tx
    .preparedQuery("INSERT INTO person (firstname,lastname) VALUES ($1,$2)").execute(Tuple.of(person.getFirstName(),person.getLastName()))
    .onItem().produceUni(id -> tx.query("SELECT LAST_INSERT_ID()").execute())
    .onItem().apply(rows -> rows.iterator().next().getInteger(0))
    .onItem().produceUni(item -> tx.commit().on().item().produceUni(v -> Uni.createFrom().item(item)))
    .on().failure().recoverWithUni(throwable -> {
        return tx.rollback().on().failure().recoverWithItem((Void) null)
            .on().item().produceUni(v -> Uni.createFrom().failure(throwable));
    })
);

SqlClientHelper将在未来版本中提供给Quarkus（希望是1.6）。您将能够简化为：

return SqlClientHelper.inTransactionUni(client, tx -> tx
    .preparedQuery("INSERT INTO person (firstname,lastname) VALUES ($1,$2)").execute(Tuple.of(person.getFirstName(),person.getLastName()))
    .onItem().produceUni(id -> tx.query("SELECT LAST_INSERT_ID()").execute())
    .onItem().apply(rows -> rows.iterator().next().getInteger(0))
);