为什么html输入提交不分配$\u POST数组值

Question

请检查代码的最后一部分，输入type=“submit”name=“save\u changes\u submit”。此表单未在$\u POST中分配。我在这里干什么？我在这里犯了什么html错误吗？我怎样才能从这次提交中获得$\u POST价值？

echo '<form action="" method="post">ID Number:<input type="number" name="id_number" value="number"><br><br><input type="submit" value="Search Product" name="id_number_submit">';

if (isset($_POST['id_number_submit'])) {
    $id_number = $_POST['id_number'];

    $q = mysqli_query($conn, "SELECT * FROM product WHERE id='$id_number'");

    $row = mysqli_fetch_array($q);

    if (empty($row)) {
        echo "Error: Invalid product id";
    }else{

    $product_name = $row['product_name'];
    $product_des = $row['product_des'];
    $product_price = $row['product_price'];


echo '<br><br><input type="number" name="product_price" value="'.$product_price.'">';
echo '<br><br><input type="text" name="product_name" value="'.$product_name.'">';
echo '<br><br><textarea rows="8" cols="100" name="product_des">'.$product_des.'</textarea><br><input type="submit" value="Save Changes" name="save_changes_submit">';

if (isset($_POST['save_changes_submit'])) {
    echo $c_product_price = $_POST['product_price'];
    echo $c_product_name = $_POST['product_name'];
    echo $c_product_des = $_POST['product_des'];
}
}
}

echo '</form>';

Answer 1

因为您没有为表单指定要处理的php文件。更改窗体的操作，如下所示：

echo '<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post">ID Number:<input type="number" name="id_number" value="number"><br><br><input type="submit" value="Search Product" name="id_number_submit">';

Answer 2

这是因为根据这个条件if（设置（$\u POST['id\u number\u submit']）！当您点击save\u changes\u submitsubmit按钮时，POST数据中没有包含id\u number\u submit。所以它不符合你的条件。改变你状况的解决方案

echo '<form action="" method="post">ID Number:<input type="number" name="id_number" value="number"><br><br><input type="submit" value="Search Product" name="id_number_submit">';

if (isset($_POST['id_number_submit'])) {
    $id_number = $_POST['id_number'];

    $q = mysqli_query($conn, "SELECT * FROM product WHERE id='$id_number'");

    $row = mysqli_fetch_array($q);

    if (empty($row)) {
        echo "Error: Invalid product id";
    }
    else{

    $product_name = $row['product_name'];
    $product_des = $row['product_des'];
    $product_price = $row['product_price'];


echo '<br><br><input type="number" name="product_price" value="'.$product_price.'">';
echo '<br><br><input type="text" name="product_name" value="'.$product_name.'">';
echo '<br><br><textarea rows="8" cols="100" name="product_des">'.$product_des.'</textarea><br><input type="submit" value="Save Changes" name="save_changes_submit">';    

   }
}
if (isset($_POST['save_changes_submit'])) {
    $c_product_price = $_POST['product_price'];
    $c_product_name = $_POST['product_name'];
    $c_product_des = $_POST['product_des'];
    echo $c_product_price;
    echo $c_product_name;
    echo $c_product_des;
}

echo '</form>';

Answer 3

if条件if（isset（$_POST[save_changes_submit]））在if（isset（$_POST[id_number_submit]）内。这就是问题所在。它在这里。

<?php
echo '<form action="" method="post">ID Number:<input type="number" name="id_number" value="number"><br><br><input type="submit" value="Search Product" name="id_number_submit">';

    if(isset($_POST['id_number_submit'])) {
        $id_number = $_POST['id_number'];

        $q = mysqli_query($conn, "SELECT * FROM product WHERE id='$id_number'");

        $row = mysqli_fetch_array($q);

        if (empty($row)){
            echo "Error: Invalid product id";
        }else{
            $product_name = $row['product_name'];
            $product_des = $row['product_des'];
            $product_price = $row['product_price'];


        echo '<br><br><input type="number" name="product_price" value="'.$product_price.'">';
        echo '<br><br><input type="text" name="product_name" value="'.$product_name.'">';
        echo '<br><br><textarea rows="8" cols="100" name="product_des">'.$product_des.'</textarea><br><input type="submit" value="Save Changes" name="save_changes_submit">';
        }
    }
    if(isset($_POST['save_changes_submit'])) {
        echo $c_product_price = $_POST['product_price'];
        echo $c_product_name = $_POST['product_name'];
        echo $c_product_des = $_POST['product_des'];
    }
    echo '</form>';
?>