Python：re.sub删除不同情况下两个分隔符之间的单词

Question

我有一个包含如下模式的字符串

"something [[remove|keep]] something [[keep]] something [[remove|remove|keep]] something" 

如何使用re。sub（）或用于编辑此字符串的其他方法

"something keep something keep something keep something"

或者

"something [[keep]] something [[keep]] something [[keep]] something". 

（我可以在以后删除[[]]s。）

我尝试使用for循环对其进行硬编码，但字符串太长，需要很长时间才能运行。

Answer 1

可以使用正则表达式：（？

import re

s = "something [[remove|keep]] something [[keep]] something [[remove|remove|keep]] something"
print(re.sub("(?<=[\[\|])[^\[]*?\|", "", s))

输出：

something [[keep]] something [[keep]] something [[keep]] something

正则表达式（？

• （？