Google pydrive将文件上载到特定文件夹

Question

我正试图上传一个文件到我的谷歌硬盘，下面的代码工作。如何指定要上载到哪个文件夹，即驱动器--shared with me--csvFolder

from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive


gauth = GoogleAuth()
gauth.LocalWebserverAuth()

drive = GoogleDrive(gauth)

file2 = drive.CreateFile()
file2.SetContentFile('new_test.csv')
file2.Upload()

Answer 1

• 您希望使用pydrive将文件上载到Google Drive中的特定文件夹

如果我的理解是正确的，这次修改怎么样？

file2 = drive.CreateFile()

file2 = drive.CreateFile({'parents': [{'id': '### folder ID ###'}]})

• 请像上面那样设置文件夹ID

• PyDrive的文档

如果这不是你想要的结果，我道歉。

当您想将文件从文件夹名称上载到特定文件夹时，此修改如何？

file2 = drive.CreateFile()
file2.SetContentFile('new_test.csv')
file2.Upload()

folderName = '###'  # Please set the folder name.

folders = drive.ListFile(
    {'q': "title='" + folderName + "' and mimeType='application/vnd.google-apps.folder' and trashed=false"}).GetList()
for folder in folders:
    if folder['title'] == folderName:
        file2 = drive.CreateFile({'parents': [{'id': folder['id']}]})
        file2.SetContentFile('new_test.csv')
        file2.Upload()

您可以使用以下代码段打印文件和/或文件夹ID

fileList = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList()
for file in fileList:
  print('Title: %s, ID: %s' % (file['title'], file['id']))
  # Get the folder ID that you want
  if(file['title'] == "To Share"):
      fileID = file['id']