使用筛选字符串筛选字符串数组并从原始数组中删除

Question

我想从包含单词Evil（filterString）的数组中删除一些元素。

let guests = ["Partner", "Evil Nice Relative 1", "Nice Relative 2", "Evil One", "another evil", "another one", "another evil is here", "strange Evil is here", "someone Nicer", "Ugly Evil Bad"];

const filteredArray = [];
const filterString = "Evil";

function checkEvil() {
    guests.filter((element, index) => {
        if (element.toLowerCase().indexOf(filterString.toLowerCase()) !== -1) {
            console.log(index);
            guests.splice(index,1);
        } else {
            filteredArray.push(element);
        }
    });
    console.log(guests);
}

以下是我从原始阵列（来宾）获得的信息：

    ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer']

只希望客人数组更新一旦所需的字符串（邪恶）被过滤。

Answer 1

<script>
    var list = ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer'];
    var new_list = [];

    for(var i=0; i<list.length; i++) {
        if(!list[i].toLowerCase().includes('evil')) {
            new_list.push(list[i]);
        }
    }

    console.log(new_list);
</script>

Answer 2

定义一个模式，然后根据它进行过滤

var arr = ['Partner', 'Nice Relative 2', 'another evil', 'another one', 'strange Evil is here', 'someone Nicer'];
const PATTERN = 'EVIL';
arr = arr.filter(str => str.toUpperCase().indexOf(PATTERN) === -1);

Answer 3

由于您希望对原始数组进行变异，因此可以执行以下操作：

let guests = [
  "Partner",
  "Evil Nice Relative 1",
  "Nice Relative 2",
  "Evil One",
  "another evil",
  "another one",
  "another evil is here",
  "strange Evil is here",
  "someone Nicer",
  "Ugly Evil Bad",
];

const filterString = "Evil";

function checkEvil() {
  for (let i = guests.length - 1; i >= 0; i--) {
    const element = guests[i];
    if (element.toLowerCase().indexOf(filterString.toLowerCase()) !== -1) {
      guests.splice(i, 1);
    }
  }
  console.log(guests);
}

checkEvil();