使用Java-Java中的基本身份验证连接到URL。网ConnectException:连接被拒绝：连接

Question

我试图连接到一个需要基本身份验证的网站，但我得到了一个java。网ConnectException:拒绝连接：连接，我无法获取内容，基本身份验证依赖于Base64编码的“Authorization”标头，其值由单词“Basic”后跟空格，后跟Base64编码的名称：password组成。当然，使用浏览器我可以得到我想要的正确的json文件

    public static void main(String[] args) {

            try {

System.setProperty("http.proxyHost", PROXY_HOST);
            System.setProperty("http.proxyPort", PROXY_PORT);
            setAuthenticator();

                String webPage = "https://foo.com/developers/apps.json";


                String name = "myUserName";
                String password = "myPassword";

                String authString = name + ":" + password;
                System.out.println("auth string: " + authString);
                byte[] authEncBytes = Base64.encodeBase64(authString.getBytes());
                String authStringEnc = new String(authEncBytes);
                System.out.println("Base64 encoded auth string: " + authStringEnc);

                URL url = new URL(webPage);
                URLConnection urlConnection = url.openConnection();

                String encoded = new String (base64Encode(new String("j0a3t:d3jk6ft")));
                urlConnection.setRequestProperty("Proxy-Authorization", "Basic " + encoded);

                urlConnection.setRequestProperty("Authorization", "Basic " + authStringEnc);
                InputStream is = urlConnection.getInputStream();
                InputStreamReader isr = new InputStreamReader(is);

                int numCharsRead;
                char[] charArray = new char[1024];
                StringBuffer sb = new StringBuffer();
                while ((numCharsRead = isr.read(charArray)) > 0) {
                    sb.append(charArray, 0, numCharsRead);
                }
                String result = sb.toString();

                System.out.println("*** BEGIN ***");
                System.out.println(result);
                System.out.println("*** END ***");
            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

        }

我在另一个程序中得到了相同的结果：

public class Application {

    public static void main(String[] args) throws ClientProtocolException, IOException {


        DefaultHttpClient httpclient = new DefaultHttpClient();

         HttpHost target = new HttpHost("foo.com", 80, "http");
         HttpGet getRequest = new HttpGet("/developers/apps.json");

         HttpResponse httpResponse = httpclient.execute(target, getRequest);
         HttpEntity entity = httpResponse.getEntity();

    }
}

这里是printStackTrace：

Base64 encoded auth string: cmljYXJkLm9sbGVAZ21hBWwuY25tOkljb17vZmNvaWwxMDA=
java.net.ConnectException: Connection refused: connect
    at java.net.PlainSocketImpl.socketConnect(Native Method)
    at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:351)
    at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:213)
    at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:200)
    at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366)
    at java.net.Socket.connect(Socket.java:529)
    at com.sun.net.ssl.internal.ssl.SSLSocketImpl.connect(SSLSocketImpl.java:564)
    at com.sun.net.ssl.internal.ssl.BaseSSLSocketImpl.connect(BaseSSLSocketImpl.java:141)
    at sun.net.NetworkClient.doConnect(NetworkClient.java:163)
    at sun.net.www.http.HttpClient.openServer(HttpClient.java:395)
    at sun.net.www.http.HttpClient.openServer(HttpClient.java:530)
    at sun.net.www.protocol.https.HttpsClient.<init>(HttpsClient.java:272)
    at sun.net.www.protocol.https.HttpsClient.New(HttpsClient.java:329)
    at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.getNewHttpClient(AbstractDelegateHttpsURLConnection.java:172)
    at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:911)
    at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(AbstractDelegateHttpsURLConnection.java:158)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1172)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:234)
    at com.sigfox.tests.ConnectToUrlUsingBasicAuthentication.main(ConnectToUrlUsingBasicAuthentication.java:46)

Answer 1

试着去掉那些线

System.setProperty("http.proxyHost", PROXY_HOST);
System.setProperty("http.proxyPort", PROXY_PORT);

它将显示是否是代理问题。

Answer 2

从表面上看，这似乎是一个代理身份验证错误。尝试使用Apache HC 4. x，Apache文档检查它

如果您使用的是windows代理服务器，请尝试使用NTLM身份验证（第4.7节）

对于第一个过程，尝试通过添加授权头（就像您在代码中所做的那样）进行抢占式身份验证，这样您就可以跳过401

Answer 3

要小心区别Proxy身份验证和URI身份验证。

这里有一个uri身份验证的示例[如果需要对uri进行身份验证]：

        BASE64Encoder encoder = new BASE64Encoder();//import sun.misc.BASE64Encoder;
        String authString = name + ":" + password;
        String authStringEncoded = encoder.encode(authString.getBytes());
        setHeader("Authorization", "Basic " + authStringEncoded);

这适用于代理身份验证[如果您需要通过代理进入internet]：

            BASE64Encoder encoder = new BASE64Encoder();
            String authString = name + ":" + password;
            String authStringEncoded = encoder.encode(authString.getBytes());
            setHeader("Proxy-Authorization", "Basic " + authStringEncoded);

也许，同样，您可以探测Apache实用程序以获得正确的编码用户名/密码

类似于以下伪代码：

Header  auth_header=
 new DigestScheme().authenticate(new UsernamePasswordCredentials(authUser.asString(),
                                                                 authPwd.asString()),
                                                       commonsHttpRequest,
                                                       new BasicHttpContext());

之后，只需：

urlConnection。setRequestProperty（“Authorization”，auth_header.getValue（））；