Python运行命令启动服务器，然后继续我的主程序

Question

我想用python代码使用命令启动服务器，但主程序到此为止。

如何修改代码，让服务器启动，然后继续我的主程序代码。

这是我下面的python代码。

import os
os.system('/usr/local/bin/python3.7 -m pyxtermjs')
print("Hello")  

下面是我的控制台输出

serving on http://127.0.0.1:5000
 * Serving Flask app "pyxtermjs.app" (lazy loading)
 * Environment: production
   WARNING: This is a development server. Do not use it in a production deployment.
   Use a production WSGI server instead.
 * Debug mode: off
WebSocket transport not available. Install eventlet or gevent and gevent-websocket for improved performance.
 * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)

Answer 1

您应该使用子流程。波本，就像这里建议的那样

subprocess.Popen(["/usr/local/bin/python3.7", "-m", "pyxtermjs"])

Answer 2

您可以使用线程进行多进程：

import os
from threading import Thread

def pro(): # Define a function to add to the Thread
    os.system('/usr/local/bin/python3.7 -m pyxtermjs')

program = Thread(target=pro) # Define the Thread with the function

program.start() # Start the Thread

print('Hello World')