如何访问具有特定类属性值的类实例？

Question

我正在用Python制作一个基于文本的RPG，并尝试设置地图和玩家移动。然而，我还没有弄清楚如何“链接”房间，以便玩家可以使用诸如北、南等命令从一个房间无缝移动到另一个房间。

我正在使用一个名为“Room”的类，它具有x坐标和y坐标属性。我已经制作了地图中每个“瓷砖”的实例，具有特定的x-pos和y-pos值。我要做的是根据当前的x-pos或y-pos是什么，转到“Room”类的当前实例。但是，我不知道如何根据属性值查找类实例。

下面是我的代码。任何帮助都将不胜感激。

class Room:
    def __init__(self,name,info,xpos,ypos,exits):
        self.instances.append(self)
        self.name = name
        self.info = info
        self.xpos = xpos
        self.ypos = ypos
        self.exits = exits

作为参考，房间。退出是指您可以从房间的哪些部分退出。这可能只是“s”和“n”，意味着东西两侧都有墙。

为了进一步参考，在下面的代码中，Cloc代表当前位置。我目前将其设置为：

intro_room = Room("Living Room of House", "You are in a dusty living room, in a stranger's house. You don't know how you got here. It's hard to see and your hands are tied", 100, 100, ['s','n'])
cloc = intro_room

另一段代码：

def inp():
    basic = input(">")
    if basic ==  'i':
        print(" ")
        print("This is what is in your current inventory", inventory)
    elif basic == 'h':
        print(" ")
        ### use this when programming actual game
        print("Available commands:\n-move\n-take\n-look\n-talk\n-use\n-enter")
    elif basic == 'm':
        print(" ")
        print(current_location)
    elif basic == 'description':
        print(cloc.name, cloc.info)
    elif basic == 'n':
        cloc = Room.get(ypos==ypos+1) ###try to access instance with certain instance attribute value???
        #etc. for 's', 'e', 'w'

上面的代码不起作用，因为我不知道如何执行贴图移动。

Answer 1

你真的做不到

cloc = Room.get(ypos==ypos+1)

您应该创建单独的方法来获取和设置类属性，如下所示：

def getY(self):
    return self.ypos

def setY(self, ypos):
    self.ypos = ypos

#do the same for xpos

所以

cloc = Room.get(ypos==ypos+1)

变成

currentY = cloc.getY()
cloc.setY(currentY += 1)

Answer 2

我认为最好的选择是分开的逻辑存储房间在其他类例如：

class Room:
    def __init__(self,name,info,xpos,ypos,exits):
        self.name = name
        self.info = info
        self.xpos = xpos
        self.ypos = ypos
        self.exits = exits

class RoomCollection:
    def __init__(self):
        self.rooms = []

    def add(self, room):
        self.rooms.append(room)

    def find_by_xpos(self, xpos):
        for room in self.rooms:
            if(xpos == room.xpos):
                return room
        return None

intro_room = Room("Living Room of House", "You are in a dusty living room, in a stranger's house. You don't know how you got here. It's hard to see and your hands are tied", 100, 100, ['s','n'])

all_rooms = RoomCollection()
all_rooms.add(intro_room)

room = all_rooms.find_by_xpos(100)

print(room.name)

Answer 3

您可以将所有房间组织在一个dics中，其中的关键是2元组（xpos，ypos）。然后，根据您的退出，您可以退出到不同的房间。

all_rooms = {
   (0, 0): Room(..., xpos=0, ypos=0, ...),
   (0, 1): Room(..., xpos=0, ypos=1, ...),
   ...
}

def inp():
    ...
    elif basic == "move":
        direction = input(f"Which direction? Your options are {cloc.exits}. \n>")
        if direction in cloc.exits:
            # determine new coordinate set based on direction
            new_loc = {
                'n': (cloc.xpos, cloc.ypos + 1),
                's': (cloc.xpos, cloc.ypos - 1),
                'e': (cloc.xpos + 1, cloc.ypos),
                'w': (cloc.xpos - 1, cloc.ypos),
            }[direction]
            # change current location to the new room
            cloc = all_rooms[new_loc]
        else:
            print("You can't move in that direction.")
    elif ...