不一致py'NoneType'对象没有属性'send'

Question

当我尝试运行该命令时，总是会收到以下错误消息：Discord。py'NoneType'对象没有属性'send'

import os
import json
import discord
from discord.ext import commands

def get_channel(client, message):
    with open('./data/welcome.json', 'r') as f:
        tchann = json.load(f)
    return tchann[str(message.guild.id)]

class welcome(commands.Cog):

    def __init__(self, client):
        self.client = client

    # Events
    @commands.Cog.listener()
    async def on_ready(self):
        print('Welcome script loading.')

    @commands.Cog.listener()
    async def on_member_join(self, member):
        embed=discord.Embed(title="Yoshino",
            url="http://animeex.nhely.hu/",
            description=f"asd1.",
            color=0x29FF94)

        channel = self.client.get_channel(id=get_channel)

        await channel.send(embed=embed)

    @commands.command()
    async def welcome(self, ctx, channel):
        with open('./data/welcome.json', 'r') as f:
            tchann = json.load(f)

        tchann[str(ctx.guild.id)] = channel

        with open('./data/welcome.json', 'w') as f:
            json.dump(tchann, f, indent=4)

        await ctx.send(f'Channel set: {channel}')

def setup(client):
    client.add_cog(welcome(client))

错误代码：

文件“C:\Users\NexaHn\AppData\Local\Programs\Python39\lib\site packages\discord\client.py”，第343行，在“运行”事件等待coro（*args，**kwargs）文件“K:\discord BOT\PythonX\cogs\welcome.py”，第30行，在on_成员加入等待频道。发送（嵌入=嵌入）属性错误：“非类型”对象没有属性“发送”

Answer 1

该错误表示变量通道为非类型或无。这可能意味着没有id为get\u channel的频道。您可能希望运行函数get\u channel，而不是将其作为id。

Answer 2

def get_channel(client, message):
    with open('./data/welcome.json', 'r') as f:
        tchann = json.load(f)
    return tchann[str(message.guild.id)]

channel = self.client.get_channel(id=get_channel)

get\u channel是一种方法。它需要一个int。见：

https://discordpy.readthedocs.io/en/stable/api.html?highlight=wait_for#discord.Client.get_channel

channel=self。客户get_通道（id=123456789）将是有效的（给定id123456789存在）。