JAXB：我们可以使用JAXB解组器访问和分配父类中的内部节点标记吗

Question

下面是我想要使用JAXB解组器将其转换为对象的xml：

<start>
    <name>sss</name>
    <address>
        <street1>xxx</street1>
        <street2>yyy</street2>
        <zip>121212</zip>
    </address>
</start>

是否可以在start类中访问和设置zip
下面是上述xml的根类，为了可读性，我没有完成setters和getter：

pacakge com.data

//importing packages
import javax.xml.bind.annotation.XmlElement;  
import javax.xml.bind.annotation.XmlRootElement; 

//Root element class declaration
@XmlRootElement(name="start")
public class Start {
    //elements that are in the xml
    private String name;
    private Address address;
    private int zip;

    @XmlElement(name="name")
    //setters and getters for name tag

    @XmlElement(name="address")
    //setters and getters for address tag

    @XmlElement(name="zip")
    //setters and getters for zip tag       
    public int getZip(){
        return zip;
    }
    public void setZip(int zip){
        this.zip = zip;
    }

}

Answer 1

这可以通过使用EclipseLink和@XmlPath注释来实现