如果输入的输入被认为是“无效的”，尝试继续询问输入

Question

这是我为CS类制作的文本冒险游戏的一小部分。你正在探索一座房子，你通过告诉游戏你想去北、南、东还是西来导航它
因此，我想添加一些内容，以便在输入无效输入时告诉您，如果您说拼写错误的单词，如Nroth、Suoth、Eas或Weast。这些只是例子，但希望你们知道我的意思，只要它不完全匹配北，南，东或西。在这段代码中，我将如何做到这一点？

我举了一个错误的例子，如果你在写“elif room==”的地方犯了拼写错误，我想输出这个错误“但它应该继续询问你想去哪个方向，即使你出现了错误，因为到目前为止，它继续询问你想去哪个方向，不管你输入什么，它都不会输出根据你进入哪个房间而应该说的文字。

def pickRoom(direction, room):
    if(direction == "quit") or (direction == "exit"):
        print("Better luck next time!")
        return "Exit"
    elif room == "Porch":
        if direction == "North":
            return "Pantry"
        else:
            print("That is not a valid entry!")
    elif room == "Pantry":
        if direction == "North":
            return "Kitchen"
        elif direction == "East":
            return "DiningRoom"
    elif room == "DiningRoom":
        if direction == "West":
            return "Pantry"
    elif room == "Kitchen":
        if direction == "West":
            return "LivingRoom"
        elif direction == "East":
            return "Bedroom"
    elif room ==  "Bedroom":
        if direction == "West":
            return "Kitchen"
    elif room == "LivingRoom":
        if direction == "West":
            return "Bathroom"
        elif direction == "North":
            return "Stairs"
    elif room == "Bathroom":
        if direction == "East":
            return "LivingRoom"
    elif room == "Stairs":
        if direction == "South":
            return "Bar"
    elif room == "Bar":
        if direction == "East":
            return "Shop"
    elif room == "Shop":
        if direction == "North":
            return "Closet"
        elif direction == "South":
            return "Storage"
    elif room == "Storage":
        if direction == "North":
            return "Shop"
    elif room == "Closet":
        if direction == "South":
            return "Shop"

如果您需要更大的代码部分甚至整个代码，请告诉我。用py文件来解决这个问题，谢谢。

Answer 1

您可以尝试根据正确选择列表进行测试。我希望这有帮助！

if room in roomList:
    # availableDirection is a dictionary that 
    # has rooms as keys and valid directions as values.
    if direction in availableDirection[room]:
        # return the next room from a dictionary representing the 
        # current room where the key is direction and value is the next room.
    else:
        return "Invalid direction"
else:
    return "Invalid room"

Answer 2

我不知道你需要什么，但这可能会有所帮助：

directions = ["south", "west", "east", "north"]
while True:
    move = input("Choose which way you would like to go\n")
    if move.lower() in directions:
        print("You have chosen to go " + move)
    else:
        print("Invalid move!")

对于只是有一个想法，这是一个输出：

>>Choose which way you would like to go
north
>>You have chosen to go north
>>Choose which way you would like to go
North
>>You have chosen to go North
>>Choose which way you would like to go
nothr
>>Invalid move!
>>Choose which way you would like to go

Answer 3

elif room.lower() in ('perch','peach','pooch'):

你只需要列出一张你想指出的所有拼写错误的大单子。如果他们所做的选择不正确，请检查他们输入的值是否在此列表中。