虽然循环输入为false

Question

import random
print("Welcome to the Number Guessing Game!")
number=random.randint(1,100)
print("I'm thinking of a number between 1 and 100.")
print(number)

def guess(lives):
    guess_number=int(input("Make a guess: "))    
    while guess_number!=number and lives>0: 
        if guess_number>number:
            print("Too High")
          
        elif guess_number<number:
            print("Too Low")
           
        else:
            print(f"You got it! The answer was {number}")
         
        if lives==0:
            print("You are out of moves.YOu loose")
        else:
            print(f"You have {lives-1} attempts remaining to guess the number")
            print("Guess Again:")
            guess(lives-1)

def set_lives():
    level=input("Choose a difficulty.Type 'easy' or 'hard': ")
    if level=="easy":
        lives=10
    else:
        lives=5
    return lives   

guess(set_lives())

在生命数==0之后，while语句为false，必须退出循环。但在这种情况下，即使循环为false，也会执行循环。

Answer 1

我可以看出，我们可以通过简化解决方案来解决这个问题，我们只需要更改guess函数，下面是代码，我将对此进行解释：

def guess(lives):
while lives > 0:
    guess_number = int(input("Make a guess: "))
    if guess_number == number:
        print(f"You got it! The answer was {number}")
        return

    if guess_number > number:
        print("Too High")

    elif guess_number < number:
        print("Too Low")
    lives -= 1
    print(f"You have {lives} attempts remaining to guess the number")

print("You are out of moves. You loose")

现在这段代码说的是：

1-我们需要至少循环{生命数量}次

2-如果用户猜测的{guess\u number}是==数字，那么打印“你知道了！答案是…”然后return语句将退出函数，所以我们只有一个成功的故事，这就是它/

3-另外2个if条件仍然会循环，因为用户没有得到所需的猜测。

4-如果循环已经完成，而我们仍然在函数中，这意味着用户在没有正确答案的情况下完成了他的{lives}，因此它将打印“你没有动作了。你松开了”