用Jackson创建嵌套json的平面对象表单

Question

我知道Jackson允许使用@jsonunwrapped创建平面json

public class Person {
    public int age;
    @JsonUnwrapped public Name name;

    public class Name {
        public String first, last;
    }
}

将序列化为

{"age" : 99, "first" : "Name", "last" : "Surname"}

public class Person {
    public int age;
    public String firstName, lastName;
}

{"age" : 99, "name" : {"first" : "Name", "last" : "Surname"}}

这可能使用Jackson1.9吗？

Answer 1

当我在寻找同样的问题时，我偶然发现了这个相当古老的问题。我最后做了这个：

public class Person {
  public int age;

  @JsonIgnore
  public String firstName, lastName;

  protected void setName(PersonName name) {
    firstName = name.first;
    lastName = name.last;
  }

  protected PersonName getName() {
    return new PersonName(firstName, lastName);
  }

  protected static class PersonName {
    private final String first, last;

    @JsonCreator
    public PersonName(@JsonProperty("first") String first, @JsonProperty("last") String last) {
      this.first = first;
      this.last = last;
    }
  }
}