如何使用Java Springboot返回zip文件流

Question

我使用Springboot，我想生成zip文件，然后返回前端。

@PostMapping(value="/export", produces = MediaType.APPLICATION_OCTET_STREAM_VALUE)
public ResponseEntity<ZipOutputStream> export() {
    // customService.generateZipStream() is a service method that can 
    //generate zip file using ZipOutputStream and then return this stream
    ZipOutputStream zipOut = customService.generateZipStream();
    return ResponseEntity
                  .ok()
                  .header("Content-Disposition", "attachment;filename=export.zip")
                  .header("Content-Type","application/octet-stream")
                  .body(zipOut)
}

spring.HttpMediaTypeNotAcceptableException: Could not find acceptable representation

   // pseudocode
   .body(out -> { 
                   ZipOutputStream zipOut = new ZipOutputStream(out));
                   zipOut.putEntry(...);
                   zipOut.write(...);
                   zipOut.closeEntry();
                   ... balabala
                }

Answer 1

您可以尝试将其作为字节数组发回：

ByteArrayOutputStream bos = new ByteArrayOutputStream();

ZipOutputStream zipOut = customService.generateZipStream();

int count;
byte data[] = new byte[2048];
BufferedInputStream entryStream = new BufferedInputStream(is, 2048);
while ((count = entryStream.read(data, 0, 2048)) != -1) {
    zos.write( data, 0, count );
}
entryStream.close();

return ResponseEntity
              .ok()
              .header("Content-Disposition", "attachment;filename=export.zip")
              .header("Content-Type","application/octet-stream")
              .body(bos.toByteArray());

考虑您需要将返回类型更改为responseentity 。