如何使用Java将文件从Zip文件读取到内存中？

Question

我从SUN网站（http://java.sun.com/developer/technicalArticles/Programming/compression/）找到了示例，但是它返回BufferedOutputStream。但是我想将ZipEntry文件作为InputStream，然后处理下一个文件。那可能吗？我的程序无法访问硬盘，因此它甚至无法临时保存文件。

import java.io.*;
import java.util.zip.*;

public class UnZip {
   final int BUFFER = 2048;
   public static void main (String argv[]) {
      try {
         BufferedOutputStream dest = null;
         FileInputStream fis = new 
       FileInputStream(argv[0]);
         ZipInputStream zis = new 
       ZipInputStream(new BufferedInputStream(fis));
         ZipEntry entry;
         while((entry = zis.getNextEntry()) != null) {
            System.out.println("Extracting: " +entry);
            int count;
            byte data[] = new byte[BUFFER];
            // write the files to the disk
            FileOutputStream fos = new 
          FileOutputStream(entry.getName());
            dest = new 
              BufferedOutputStream(fos, BUFFER);
            while ((count = zis.read(data, 0, BUFFER)) 
              != -1) {
               dest.write(data, 0, count);
            }
            dest.flush();
            dest.close();
         }
         zis.close();
      } catch(Exception e) {
         e.printStackTrace();
      }
   }
}

Answer 1

好吧，只需将将文件写入文件的部分更改为您要处理的数据即可。

while((entry = zis.getNextEntry()) != null) {
    System.out.println("Extracting: " + entry);
    int count;
    byte[] data = new byte[BUFFER];
    String filename = entry.getName();
    System.out.println("Filename: " + filename);
    while ((count = zis.read(data, 0, BUFFER)) != -1) {
       // Do whatever you want with the data variable
       System.out.println(data);
    }
}