克隆包含所有关系的雄辩对象？

Question

有没有办法轻松克隆一个有说服力的对象，包括它的所有关系？

例如，如果我有以下表格：

users ( id, name, email )
roles ( id, name )
user_roles ( user_id, role_id )

除了在users表中创建新行（除id外，所有列都相同）外，还应在user\u roles表中创建新行，将相同的角色分配给新用户。

像这样的东西：

$user = User::find(1);
$new_user = $user->clone();

其中用户模型具有

class User extends Eloquent {
    public function roles() {
        return $this->hasMany('Role', 'user_roles');
    }
}

Answer 1

拉威尔5号。测试与许多关系。

$model = User::find($id);

$model->load('invoices');

$newModel = $model->replicate();
$newModel->push();


foreach($model->getRelations() as $relation => $items){
    foreach($items as $item){
        unset($item->id);
        $newModel->{$relation}()->create($item->toArray());
    }
}

Answer 2

您也可以尝试eloquent提供的复制功能：

http://laravel.com/api/4.2/Illuminate/Database/Eloquent/Model.html#method_replicate

$user = User::find(1);
$new_user = $user->replicate();
$new_user->push();

Answer 3

在laravel 4.2中测试是否存在归属关系

如果您在模型中：

    //copy attributes
    $new = $this->replicate();

    //save model before you recreate relations (so it has an id)
    $new->push();

    //reset relations on EXISTING MODEL (this way you can control which ones will be loaded
    $this->relations = [];

    //load relations on EXISTING MODEL
    $this->load('relation1','relation2');

    //re-sync everything
    foreach ($this->relations as $relationName => $values){
        $new->{$relationName}()->sync($values);
    }