Lombok@Singular在构造函数上使用@Builder的子类中没有影响

Question

所以我刚刚发现了Lombok@builder注释，我喜欢它。尤其是对于集合的@singular注释。

在继承的情况下，我读到为子类创建构建器的最有效方法如下：

@Data
@AllArgsConstructor
class User {
    private String username;
    private String password;
    private String email;
}

@Data
@EqualsAndHashCode(callSuper = true)
public class Customer extends User {

    @Singular
    private List<Order> orders;

    @Builder
    public Customer(String username, String password, String email, List<Order> orders) {
        super(username, password, email);
        this.orders = orders;
    }   
}

Answer 1

您可以将@singular注释添加到Customer类的构造函数中的List Orders 参数，以获得所需的效果。

@Builder
public Customer(String username, String password, String email, @Singular List<Order> orders) {
    super(username, password, email);
    this.orders = orders;
}