如何从A-Z排序数组列表？

Question

Default Browser    Google     www.Google.com     14/12/2013
Default Browser    BBC        www.BBC.com        13/12/2015
Default Browser    Amazon     www.Amazon.com     11/11/2014

Default Browser    Amazon     www.Amazon.com     11/11/2014
Default Browser    BBC        www.BBC.com        13/12/2015
Default Browser    Google     www.Google.com     14/12/2013

这是我试过的，但不起作用。

 int j = mCur.getCount();
 String[] mType = new String[j];
 String[] mTitles = new String[j];
 String[] murls = new String[j];
 long[] date = new long[j];

 for (int q=0; q<(j-1); q++) {
                String a = (mTitles[q]).toLowerCase();
                String b = (mTitles[q+1].toLowerCase());

                char[] c = a.toCharArray();
                char[] d = b.toCharArray();

                String temp, temp2, temp3 = null;
                long temp4 = 0;

                int lenc = c.length;
                int lend = d.length;
                int min =0;
                int count =0;

                if (lenc < lend)
                    min = lenc;
                else
                    min = lend;

                    if (c[count] > d[count]) {
                        temp = mTitles[count];
                        temp2 = mType[count];
                        temp3 = murls[count];
                        temp4 = date[count];

                        mTitles[count] = mTitles[count + 1];
                        mType[count] = mType[count + 1];
                        murls[count] = murls[count + 1];
                        date[count] = date[count + 1];

                        mTitles[count + 1] = temp;
                        mType[count + 1] = temp2;
                        murls[count + 1] = temp3;
                        date[count + 1] = temp4;
                    } else if (c[count] == d[count]) {
                        for (int w = 1; w < min; w++) {
                            if (c[w] > d[w]) {
                                temp = mTitles[w];
                                temp2 = mType[w];
                                temp3 = murls[w];
                                temp4 = date[w];

                                mTitles[w] = mTitles[w + 1];
                                mType[w] = mType[w + 1];
                                murls[w] = murls[w + 1];
                                date[w] = date[w + 1];

                                mTitles[w + 1] = temp;
                                mType[w + 1] = temp2;
                                murls[w + 1] = temp3;
                                date[w + 1] = temp4;
                            }
                        }
                    }
            }

Answer 1

以上的回答给出了在Java中高效排序数组列表的最佳例子。

在此之前，请阅读上述答案的描述

我只是简化了上面的答案，让你更好地理解，它给出了你所需要的确切输出。

ArrayList<UserContainer> userList = new ArrayList<>();
    userList.add(new UserContainer("www.Google.com", "Google", "14/12/2013"));
    userList.add(new UserContainer("www.BBC.com", "BBC", "13/12/2015"));
    userList.add(new UserContainer("www.Amazon.com", "Amazon", "11/11/2014"));

    Log.i("Before Sorting :", "==========================>>");
    for (UserContainer obj : userList) {
        System.out.println("Default Browser: \t" + obj.name + "\t" + obj.date + "\t" + obj.webSite);
    }

    Collections.sort(userList, new Comparator<UserContainer>() {
        @Override
        public int compare(UserContainer first, UserContainer second) {
            return first.name.compareToIgnoreCase(second.name);
        }
    });


    Log.i("After Sorting :", "==========================>>");
    for (UserContainer obj : userList) {
        System.out.println("Default Browser: \t" + obj.name + "\t" + obj.date + "\t" + obj.webSite);
    }

    public class UserContainer {
    public UserContainer(String webSite, String name, String date) {
        this.webSite = webSite;
        this.name = name;
        this.date = date;
    }

    public String webSite = "";
    public String name = "";
    public String date = "";
}