获取随机值android firebase java

Question

我想通过在Java中使用push（）从列表中获得一个随机。

                Firebase publRef = f.child("Language").child("German").child("Message");
                Firebase newPublRef = publRef.push();
                Map<String, Object> publ = new HashMap<String, Object>();
                publ.put("pubMsg", writeMsgField.getText().toString());
                newPublRef.setValue(publ);

Language
   German
      Message
        -Jf6ShYy7niHrqg_x4Tc: "Tomorrow is very windy"
        -Jf9v0xHAxINUUANrORU: "Today is very windy and rainy"

        Firebase f = new Firebase("https://myapp.firebaseio.com/Language/German/Message/");             
    f.addValueEventListener(new ValueEventListener() {

        public void onDataChange(DataSnapshot snapshot) {
            disp_msg = (TextView)findViewById(R.id.display_msg);
            //disp_msg.setText(snapshot.getValue().toString());
            Iterable<DataSnapshot> ds = snapshot.getChildren();
            Iterator<DataSnapshot> ids = ds.iterator();
            Map<String, Object> newPost = (Map<String, Object>) ids.next().getValue();
            String msg = newPost.get("pubMsg").toString();
            disp_msg.setText(msg.toString());

        }

        //getting maximum number of children
        long allNum = snapshot.getChildrenCount();
        int maxNum = (int)allNum;

        //getting the random integer from number of children
        int randomNum = new Random().nextInt(maxNum);

        int count = 0;

        //has next will check the next value while count is used as a position substitute.
        while(ids.hasNext() && count < randomNum) {
            ids.next();
            count ++; // used as positioning.
           }

Answer 1

找出数据库中可能的值的数目，然后在

int random = new Random().nextInt(numvals);

并选择数据库中的“随机”th条目。