Javafx时间线获取当前周期时间

Question

Timeline timeline = new Timeline();
    timeline = new Timeline(new KeyFrame(Duration.ZERO, new EventHandler<ActionEvent>() {
        @Override
        public void handle(ActionEvent actionEvent) {
            System.out.println("Counting");
            //myFunction(currentCycleStep) <------
        }
    }), new KeyFrame(Duration.seconds(SimulationController.speed)));


    timeline.setCycleCount(5);
    timeline.play();

Answer 1

我认为没有直接的方法从一个时间线得到实际的周期。

你可以为此写你自己的财产。下面是一个示例，它监视currentTime，并在每次更改“方向”时增加我们自创建的属性的值。

示例：

currentTime: 1s
currentTime: 2s
currentTime: 3s
currentTime: 0s  <--------- increment actual cycle
currentTime: 1s

currentTime: 1s
currentTime: 2s
currentTime: 3s
currentTime: 2s  <--------- increment actual cycle
currentTime: 1s

@Override
public void start(Stage primaryStage) throws Exception {
    SimpleStringProperty testProperty = new SimpleStringProperty();
    Timeline timeline = new Timeline(new KeyFrame(Duration.millis(1000), new KeyValue(testProperty, "1234")));
    timeline.setCycleCount(Timeline.INDEFINITE);

    // ----------------------------------------------------------------------
    // we create our own property for the actual cycle-index
    // ----------------------------------------------------------------------
    SimpleIntegerProperty actualCycleProperty = new SimpleIntegerProperty(0);
    timeline.currentTimeProperty().addListener((observable, oldValue, newValue) -> {
        boolean smaller = newValue.toMillis() < oldValue.toMillis();
        boolean evenCycleCount = actualCycleProperty.get() % 2 == 0;
        if ((timeline.isAutoReverse() && !evenCycleCount && !smaller)
                || ((evenCycleCount || !timeline.isAutoReverse()) && smaller)) {
            actualCycleProperty.set(actualCycleProperty.get() + 1);
        }
    });

    actualCycleProperty.addListener((observable, oldValue, newValue) -> {
        System.out.println(newValue);
    });
    timeline.play();
}