如何使用JPA、Hibernate、Springboot实现复合主键和复合外键

Question

我为这个特殊的问题找了很多，但我没有找到任何具体的解决办法。我在一个表中有一个复合主键，这个复合主键的一个字段是另一个表的复合主键的一部分。您可以说这个特定的字段是第二个表中的外键，但是在表定义中没有定义任何独占外键约束。对于第一个表中的每个rec，第二个表中可能有多条记录。我试图使用SPringBoot-JPA-Hibernate实现这一点，但无法实现。有人能帮我吗。以下是德泰：-

我有一个USER_CREDENTIAL表，其中包含以下字段：-

CREATE TABLE `INSTITUTION_USER_CREDENTIAL` (
    `INSTITUTION_USER_ID INT(10) NOT NULL,  -> AutoGeneratd
    `INSTITUTION_USER_NAME` VARCHAR(50) NOT NULL,
    `INSTITUTION_USER_PASSWORD` VARCHAR(50) NOT NULL,
    `FIRST_NAME` VARCHAR(100) NOT NULL,
    `MIDDLE_NAME` VARCHAR(100),
    `LAST_NAME` VARCHAR(100) NOT NULL,
    PRIMARY KEY (`INSTITUTION_USER_ID`,`INSTITUTION_USER_NAME`) 
   );

2）这是我的第二张桌子

CREATE TABLE `INSTITUTION_USER_CREDENTIAL_MASTER` (
`INSTITUTION_ID` INT(10) NOT NULL,  -> Autogenerated
`INSTITUTION_USER_ID`  INT(10) NOT NULL, -> Coming from 
                                           INSTITUTION_USER_CREDENTIAL
`INSTITUTION_USER_ROLE`  CHAR(02) NOT NULL, 
`INSTITUTION_USER_STATUS` CHAR(02) NOT NULL,
`INSTITUTION_NAME` VARCHAR(200) NOT NULL,
`LAST_UPDT_ID` VARCHAR(100) NOT NULL,
`LAST_UPDT_TS` DATETIME NOT NULL,
PRIMARY KEY(`INSTITUTION_ID`,`INSTITUTION_USER_ID`,`INSTITUTION_USER_ROLE`)
);

请注意，我没有在第二个表中声明任何特定的外键。我有两个@Embeddable类，对应于两个不同表的两个主键结构：-

对于INSTITUTION_USER_CREDENTIAL表：-

@Embeddable
public class InstitutionUserCredentialPrimaryKey implements Serializable{

private static final long serialVersionUID = 1L;

@Column(name = "INSTITUTION_USER_ID")
@GeneratedValue(strategy=GenerationType.AUTO)
private int institutionUserId;

@Column(name = "INSTITUTION_USER_NAME")
private String institutionUserName;
//Getter-Setters removed for clarity
}

@Entity(name = "INSTITUTION_USER_CREDENTIAL")
public class InstitutionUserCredential {

@EmbeddedId
private InstitutionUserCredentialPrimaryKey 
        institutionUserCredentialPrimaryKey;

@Column(name = "INSTITUTION_USER_PASSWORD")
private String instituteUserPassword;

@Column(name = "FIRST_NAME")
private String firstname;

@Column(name = "MIDDLE_NAME")
private String middleName;

@Column(name = "LAST_NAME")
private String lastName;

@OneToMany(mappedBy="institutionUserCredential", cascade = CascadeType.ALL)
private List<InstitutionUserCredentialMaster> 
           institutionUserCredentialMaster;
//Getter-Setter and other part of the code removed for clarity
}

@Embeddable
public class InstituteUserCredentialMasterPrimaryKey implements Serializable 
{

private static final long serialVersionUID = 1L;

@Column(name = "INSTITUTION_ID")
@GeneratedValue(strategy=GenerationType.AUTO)
private int institutionId;

@Column(name = "INSTITUTION_USER_ID")
private int institutionUserId;

@Column(name = "INSTITUTION_USER_ROLE")
private String userRole;

//Getter-Setter and other part of the code removed for clarity
}

@Entity(name = "INSTITUTION_USER_CREDENTIAL_MASTER")
 public class InstitutionUserCredentialMaster {

@EmbeddedId
private InstituteUserCredentialMasterPrimaryKey 
   instituteUserCredentialMasterPrimaryKey;

@Column(name = "INSTITUTION_USER_STATUS")
private String userStatus;

@Column(name = "INSTITUTION_NAME")
private String institutionName;

@Column(name = "LAST_UPDT_ID")
private String lastUpdateId;

@Column(name = "LAST_UPDT_TS")
private String lastUpdateTimestamp;

@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
    @JoinColumn(name="institutionUserId", referencedColumnName = 
              "INSTITUTION_USER_ID")
})
private InstitutionUserCredential institutionUserCredential;

//Getter-Setter and other part of the code removed for clarity
}

当我运行我的代码时，这会给我一个错误，比如：-

Invocation of init method failed; nested exception is 
org.hibernate.AnnotationException: 
referencedColumnNames(INSTITUTION_USER_ID) of com.bnl.application.entity.InstitutionUserCredentialMaster.institutionUserCredential referencing com.bnl.application.entity.InstitutionUserCredential not mapped to a single property

到目前为止，我所看到的涉及复合主键和外键的示例没有一个不处理任何一个特定的字段，而是更多地处理整个键结构。我正在使用MYSQL，并检查了是否可以创建具有复合主键的表，并且该复合键中的一个字段在另一个表中是外键，也是第二个表的复合主键的一部分。

赞赏任何指针

@Embeddable

公共类InstituteUserCredentialMasterPrimaryKey实现Serializable{

private static final long serialVersionUID = 1L;

@Column(name = "INSTITUTION_ID")
@GeneratedValue(strategy=GenerationType.AUTO)
private int institutionId;

@Column(name = "INSTITUTION_USER_ID")
private int institutionUserId;
// Added the institutionUserName
@Column(name = "INSTITUTION_USER_NAME")
private String institutionUserName;

@Column(name = "INSTITUTION_USER_ROLE")
private String userRole;
}

更新到实体类InsstitutionUserCredentialMaster：-

@Entity(name = "INSTITUTION_USER_CREDENTIAL_MASTER")

公共类InstitutionUserCredentialMaster

@EmbeddedId
private InstituteUserCredentialMasterPrimaryKey instituteUserCredentialMasterPrimaryKey;

@Column(name = "INSTITUTION_USER_STATUS")
private String userStatus;

@Column(name = "INSTITUTION_NAME")
private String institutionName;

@Column(name = "LAST_UPDT_ID")
private String lastUpdateId;

@Column(name = "LAST_UPDT_TS")
private String lastUpdateTimestamp;

@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
    @JoinColumn(name="institutionUserId", referencedColumnName = "INSTITUTION_USER_ID"),
    @JoinColumn(name="institutionUserName",referencedColumnName = "INSTITUTION_USER_NAME")
})
private InstitutionUserCredential institutionUserCredential;
}

Invocation of init method failed; nested exception is org.hibernate.DuplicateMappingException: Table [institution_user_credential_master] contains physical column name [institution_user_id] referred to by multiple physical column names: [institutionUserId], [INSTITUTION_USER_ID]

Answer 1

我认为问题在于您没有在JoinColumns注释中引用EmbeddedId的其他部分。您已经定义了InstitutionUserName也是主键的一部分，因此您也应该在实体InstitutionUserCredentialMaster中的外键定义中提到它。