读取文本文件并将其放入数组

Question

我读过其他一些类似于此的问题，但都使用了imports和extras，除了importjava.io.*之外，我不想使用任何imports；也没有任何名单。另外，这个is方法中的for循环是我在搞乱它，因为我无法弄清楚它。

public static int[] processFile (String filename) throws IOException, FileNotFoundException {
    BufferedReader inputReader = new BufferedReader (new InputStreamReader(new FileInputStream(filename)));
    String line;
    int[] a = new int[25];
    while (( line = inputReader.readLine()) != null){
        int intValue = Integer.parseInt(line); //converts string into int
        for (int i = 0; i < a.length; i++){
            a[intValue]++;
        }

    }
    return a;
}
 public static void printArray (int[] a) {
    for (int i = 0; i<a.length; i++) {
    System.out.println (a[i]);
    }

}public static void main(string[]args)抛出IOException,FileNotFoundException{int[]array=processFile（“C:\users\griff_000\desktople\testWeek13.txt”）；printArray（阵列）；}

Answer 1

我不清楚您的整个导入限制，您到底为什么要限制导入的数量？

不管怎样，查看您的代码，似乎对数组的概念还不是很清楚。

数组是在以下语法下访问的：

array[index] = value;

public static int[] processFile (String filename) throws IOException, FileNotFoundException{
    BufferedReader inputReader = new BufferedReader (new InputStreamReader(new FileInputStream(filename)));
    String line;

    int[] a = new int[25];

    int i = 0; // We need to maintain our own iterator when using a while loop

    while((line = inputReader.readLine()) != null){
        int intValue = Integer.parseInt(line); //converts string into int

        a[i] = intValue; // Store intValue into the array at index i

        i++; // Increment i
    }
    return a;
}

public static int[] processFile (String filename) throws IOException, FileNotFoundException{
    BufferedReader inputReader = new BufferedReader (new InputStreamReader(new FileInputStream(filename)));
    String line;

    int[] a = new int[25];

    for(int i = 0; i < a.length; i++){
        String line = inputReader.readLine(); // Move the readline code inside the loop

        if(line == null){
            // We hit EOF before we read 25 numbers, deal appropriately
        }else{
            a[i] = Integer.parseInt(line); 
        }
    }

    return a;
}