Laravel 5.2单元测试错误：BadMeodCallExc0019：调用未定义的方法照明\数据库\查询\Builder::（）

Question

我正在尝试用Laravel 5.2设置PHPUnit。我按照留档进行了简单的单元测试，但是每个测试都会抛出相同的错误：

1） CreateAccountTest:：testCreateUserWithInvalidEmail BadMethodCallException:调用未定义的方法Illumb\Database\Query\Builder:：make（）

/some/path/vendor/laravel/framework/src/Illuminate/Database/Query/Builder.php:2405 /some/path/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Builder.php:1426 /some/path/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:3526 /some/path/vendor/laravel/framework/src/Illuminate/Foundation/Testing/Concerns/MakesHttpRequests.php:504 /some/path/vendor/laravel/framework/src/Illuminate/Foundation/Testing/Concerns/MakesHttpRequests.php:504 /some/path/vendor/laravel/framework/src/Illuminate/Foundation/Testing/Concerns/MakesHttpRequests.php:73 /some/path/tests/UnitTests/CreateAccountT<--plhd##################################################################

我的单元测试看起来都与此类似，只是每次都声明不同的属性：

class CreateAccountTest extends TestCase
{

    protected $body;
    protected $app;

    protected function setUp() {
        parent::setUp();

        $this->app = factory(\App\Models\App::class)->create([
           'name' => 'Test Suite'
       ]);

        $this->body = [
            'name' => 'Doe',
            'firstName' => 'John',
            'login' => 'john.doe',
            'email' => '[e-mail]',
            'password' => 'test1324',
            'repeatPassword' => 'test1234',
            'appId' => $this->app->id
        ];
    }

    public function testCreateUserWithInvalidEmail() {
        $this->body['email'] = 'this_is_not_a_valid_email_address';

        $this->json('POST', '/profile/create', $this->body)
             ->assertResponseStatus(400);
    }

}

包含相关代码的配置文件控制器：

<?php

namespace App\Http\Controllers\Account;

use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use App\Http\Requests\Account\CreateAccountPostRequest;
use App\Models\AccessToken;
use App\Models\User;

class ProfileController extends Controller
{

    public function createUser(CreateAccountPostRequest $request) {

        $user = new User();
        $user->firstname = $request['firstName'];
        $user->name = $request['name'];
        $user->email = $request['email'];
        $user->password = $request['password'];
        $user->save();

        $accessToken = AccessToken::createAccessToken($user->id);
        $accessToken->save();

        return $this->sendSuccessResponse();
    }
}

模型工厂：

$factory->define(App\Models\App::class, function (Faker\Generator $faker) {
    $company = $faker->company;
    return [
        'name' => $company,
        'submit_description' => $faker->sentence($nbWords = 6, $variableNbWords = true),
        'subdomain' => str_replace(' ', '', $company),
        'advancedFilter' => 0,
        'isdeleted' => 0,
        'defaultlanguage' => 'en',
        'timestamp' => time()
    ];
});

stacktrace所述的第32行如下：

 $this->json('POST', '/profile/create', $this->body)
             ->assertResponseStatus(400);

根据文件，这一切看起来非常简单，我不知道这里发生了什么。

Answer 1

好吧，我知道这里发生了什么。我制作了一个字段受保护的$app意外覆盖父类中的$app字段。这将类从Laravel应用程序（illumb\Foundation\Application）转换为不存在make（）函数的illumb/Database/Eloquent/Model。这就是抛出错误的原因。

所以基本上，将$app字段重命名为$Application或其他任何方法都可以解决问题。