通过HttpUrlConnection在服务器上注册用户数据的Post请求

Question

我目前在一个项目中，我需要发送用户名，密码和电子邮件的用户注册在我的服务器上的用户。我为此使用了POST命令，因为我必须为注册一个用户发送3个值，所以我为此使用了ContentValues。下面是我的代码：

@Override
    protected String doInBackground(String... params) {
        try {
            url = new URL(params[0]);
            httpURLConnection = (HttpURLConnection) url.openConnection();
            httpURLConnection.setDoInput(true);
            httpURLConnection.setDoOutput(true);
            httpURLConnection.setRequestMethod("POST");

            ContentValues values = new ContentValues();
            values.put("email", "[e-mail]");
            values.put("password", "123");
            values.put("name","ABC");

            outputStream = httpURLConnection.getOutputStream();

            bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream));
            bufferedWriter.write(getQuery(values));
            bufferedWriter.flush();

            statusCode = httpURLConnection.getResponseCode();

            Log.i("Result",String.valueOf(statusCode));

            inputStream = new BufferedInputStream(httpURLConnection.getInputStream());

            InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
            int data = inputStreamReader.read();
            while (data != -1) {
                char current = (char) data;
                result += current;
                data = inputStreamReader.read();
            }

            JSONObject jsonObject = new JSONObject(result);

            Log.i("Result",String.valueOf(jsonObject));

            if (statusCode == 200) {
                inputStream = new BufferedInputStream(httpURLConnection.getInputStream());

                Log.i("Result","Correct Data Returned");

                JSONObject jsonObject = new JSONObject(response);

                return true;

            } else {
                Log.i("Result","Data not returned");
                return false;
            }

        } catch (Exception e) {

            e.printStackTrace();
        } finally {
            try {
                if (inputStream != null) {
                    inputStream.close();
                }
                if (outputStream != null) {
                    outputStream.close();
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
        return null;
    }

private String getQuery(ContentValues values) throws UnsupportedEncodingException
    {
        StringBuilder result = new StringBuilder();
        boolean first = true;

        for (Map.Entry<String, Object> entry : values.valueSet())
        {
            if (first)
                first = false;
            else
                result.append("&");

            result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
            result.append("=");
            result.append(URLEncoder.encode(String.valueOf(entry.getValue()), "UTF-8"));
        }

        Log.i("Result",result.toString());

        return result.toString();
    }

Result: name=ABC&email=abc%40xyz.com&password=123
Result: 422
System.err: java.io.FileNotFoundException: http://docpanel.myworkdetails.com/api/auth/register

"errors": {
     "email": [
       "The email field is required."
     ],
     "password": [
       "The password field is required."
     ],
     "name": [
       "The password field is required."
     ]
   },
   "status_code": 422

Answer 1

为什么不直接将url与参数连接起来呢？

然后请求如下所示：“http://example.com/test?param1=a&param2=b&param3=c”