我试图使用HttpURLConnection执行post请求,但不知道如何正确执行。
我可以使用以下代码成功地使用Android AsyncHttp客户端执行请求:
AsyncHttpClient httpClient = new AsyncHttpClient();
httpClient.addHeader("Content-type", "application/json");
httpClient.setUserAgent("GYUserAgentAndroid");
String jsonParamsString = "{\"key\":\"value\"}";
RequestParams requestParams = new RequestParams("request", jsonParamsString);
httpClient.post("<server url>", requestParams, jsonHttpResponseHandler);
可以在台式机上使用curl执行相同的请求:
curl -A "GYUserAgentAndroid" -d 'request={"key":"value"}' '<server url>'
这两种方法都给了我来自服务器的预期响应。
现在我想使用HttpURLConntions执行相同的请求。问题是我不知道如何正确地执行它。我尝试过这样的事情:
URL url = new URL("<server url>");
HttpURLConnection httpUrlConnection = (HttpURLConnection) url.openConnection();
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setDoInput(true);
httpUrlConnection.setRequestMethod("POST");
httpUrlConnection.setRequestProperty("User-Agent", "GYUserAgentAndroid");
httpUrlConnection.setRequestProperty("Content-Type", "application/json");
httpUrlConnection.setUseCaches (false);
DataOutputStream outputStream = new DataOutputStream(httpUrlConnection.getOutputStream());
// what should I write here to output stream to post params to server ?
outputStream.flush();
outputStream.close();
// get response
InputStream responseStream = new BufferedInputStream(httpUrlConnection.getInputStream());
BufferedReader responseStreamReader = new BufferedReader(new InputStreamReader(responseStream));
String line = "";
StringBuilder stringBuilder = new StringBuilder();
while ((line = responseStreamReader.readLine()) != null) {
stringBuilder.append(line);
}
responseStreamReader.close();
String response = stringBuilder.toString();
JSONObject jsonResponse = new JSONObject(response);
// the response is not I'm expecting
return jsonResponse;
如何正确地将与使用AsyncHttpClient和curl的工作示例中相同的数据写入HttpURLConnection输出流?
先谢谢你。
这里您有一个使用HttpUrlConntions的请求,您缺少的只是从服务器读取值。
try {
JSONObject job = new JSONObject(log);
String param1 = job.getString("AuditScheduleDetailID");
String param2 = job.getString("AuditAnswerId");
String param3 = job.getString("LocalFindingID");
String param4 = job.getString("LocalMediaID");
String param5 = job.getString("Files");
String param6 = job.getString("ExtFiles");
Log.d("hasil json", param1 + param2 + param3 + param4 + param5 + param6 + " Kelar id " +
"pertama");
URL url = new URL("myurl");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json;charset=UTF-8");
conn.setRequestProperty("Accept", "application/json");
conn.setDoOutput(true);
conn.setDoInput(true);
JSONObject jsonParam = new JSONObject();
jsonParam.put("AuditScheduleDetailID", param1);
jsonParam.put("AuditAnswerId", param2);
jsonParam.put("LocalFindingID", param3);
jsonParam.put("LocalMediaID", param4);
jsonParam.put("Files", param5);
jsonParam.put("ExtFiles", param6);
Log.i("JSON", jsonParam.toString());
DataOutputStream os = new DataOutputStream(conn.getOutputStream());
//os.writeBytes(URLEncoder.encode(jsonParam.toString(), "UTF-8"));
os.writeBytes(jsonParam.toString());
os.flush();
os.close();
InputStream is = null;
if(conn.getResponseCode() == HttpURLConnection.HTTP_OK){
is = conn.getInputStream();// is is inputstream
} else {
is = conn.getErrorStream();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
String response = sb.toString();
//HERE YOU HAVE THE VALUE FROM THE SERVER
Log.d("Your Data", response);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
conn.disconnect();
} catch (JSONException | IOException e) {
e.printStackTrace();
}
您可以使用以下内容来发布参数
outputStream.writeBytes(jsonParamsString);
outputStream.flush();
outputStream.close();
public String getJson(String url,JSONObject params){
try {
URL _url = new URL(url);
HttpURLConnection urlConn =(HttpURLConnection)_url.openConnection();
urlConn.setRequestMethod(POSTMETHOD);
urlConn.setRequestProperty("Content-Type", "applicaiton/json; charset=utf-8");
urlConn.setRequestProperty("Accept", "applicaiton/json");
urlConn.setDoOutput(true);
urlConn.connect();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(urlConn.getOutputStream()));
writer.write(params.toString());
writer.flush();
writer.close();
if(urlConn.getResponseCode() == HttpURLConnection.HTTP_OK){
is = urlConn.getInputStream();// is is inputstream
} else {
is = urlConn.getErrorStream();
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
response = sb.toString();
Log.e("JSON", response);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
return response ;
}
我正在尝试进行http补丁请求,但我总是得到404错误,所以可能是我的连接设置不正确: 我收到404错误,未找到。当使用Postman执行相同的请求时,这是有效的…谢谢你的帮助。
我正在尝试使用HttpUrlConnection发送帖子。一切看起来都很好,但它保持返回400,就好像参数不是在DataOutputStream中发送的,或者是以错误的方式发送的。 这是返回的内容: 这很奇怪,因为这个卷曲正常工作: 它会返回我想要的访问令牌
我被夹在中间。我想实现一个POST方法,使用HttpUrlConnection向服务器发送注册用户的电子邮件、名称和密码。以下是我的代码: 我不知道我在哪里犯了错误。我收到以下回复 空格后的“0”是超文本传输协议响应代码返回的响应代码。当我在浏览器中尝试时,我的网址是正确的。我不知道我在哪里犯了错误;是我的服务器故障还是我的代码有错误,因为我不认为我的代码有任何交互处理。 我是Android开发的
如何使用< code>HttpURLConnection设置HTTP请求方法MOVE? 使用< code>HttpURLConnection或依赖于该类的库,代码将引发异常< code >,其原因是:Java . net . protocol exception:Invalid HTTP method:MOVE 。所以我猜Java平台不支持< code>MOVE方法。 是否有针对此问题/限制的补丁
问题内容: 使用HttpURLConnection时,如果我们不“获取”并使用它,是否需要关闭InputStream? 即安全吗? 其次, 在完全读取所有内容之前 关闭InputStream是否安全? 是否存在使基础套接字处于ESTABLISHED或CLOSE_WAIT状态的风险? 问题答案: 在读取所有内容之前关闭InputStream是否安全? 您需要先关闭输入流中的所有数据,然后再关闭它,以
我试图使用android HttpUrlConnection进行POST请求。首先,我从这里使用GET请求的示例: http://developer.android.com/training/basics/network-ops/connecting.html#http-客户 它工作得非常好(例如,我得到了google.com页面)。然后我做了一些更改以发出POST请求:更改POST上的请求方法: