NoSuChelementException：使用给定的搜索参数无法在页面上找到元素

Question

我正在使用的代码：

public class SafariTest {
private static IOSDriver iOSDriver;
private WebElement loginSettingsButton;
@Before
public void preTest() throws MalformedURLException {
    DesiredCapabilities capabilities = new DesiredCapabilities();

    capabilities.setCapability(MobileCapabilityType.DEVICE_NAME, "xxxx");
    capabilities.setCapability(MobileCapabilityType.PLATFORM_NAME, "iOS");
    capabilities.setCapability(MobileCapabilityType.PLATFORM_VERSION, "12.1");

    capabilities.setCapability(MobileCapabilityType.AUTOMATION_NAME, "XCUITest");
    capabilities.setCapability(MobileCapabilityType.UDID, "xxxx");
    capabilities.setCapability(MobileCapabilityType.APP,"/xxx.app");

    iOSDriver = new IOSDriver(new URL("http://127.0.0.1:4723/wd/hub"), capabilities);

    //webDriver = new AppiumDriver(new URL("http://127.0.0.1:4723/wd/hub"), capabilities);
}
@Test
public void testCase(){
    WebDriverWait wait = new WebDriverWait(iOSDriver, 15); 
loginSettingsButton = iOSDriver.findElement(By.name("loginSettingsButton"));
loginSettingsButton.click();
}

@After
public void finishTest(){
    //  webDriver.quit();
}

public static void setContextToWebview(){
    Set<String> availableContexts = iOSDriver.getContextHandles();
    availableContexts.stream()
            .filter(context -> context.toLowerCase().contains("webview"))
            .forEach(newcontext -> iOSDriver.context(newcontext));
}

}

我得到的错误：

Answer 1

而不是使用findElement（by.name（“...”））方法请尝试使用findElementByAccessibilityId（“LoginSettingsButton”）

loginSettingsButton = iOSDriver.findElementByAccessibiltyId("loginSettingsButton");

确保将loginSettingsButton中的元素作为automationId（即内容描述）呈现

对于Appium，xpath不建议使用name。在使用Appium时，必须使用accessibilty id或id。如果您没有像cont-desc、resource-id或id这样的自动化id，您可以要求您的开发团队添加它