未捕获错误：调用未定义函数mysql_escape_string()

Question

<?php
require("config.php");
?>
<?php
if(isset($_POST['submit'])){

$email1 = $_POST['email1'];
$email2 = $_POST['email2'];
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];

if($email1 == $email2) {
    if($pass1 == $pass2) {
//All good. Nastavi broo.

$name = mysql_escape_string($_POST['name']);
$lname = mysql_escape_string($_POST['lname']);
$uname = mysql_escape_string($_POST['uname']);
$email1 = mysql_escape_string($email1);
$email2 = mysql_escape_string($email2);
$pass1 = mysql_escape_string($pass1);
$pass2 = mysql_escape_string($pass2);

mysql_query("INSERT INTO `users` (`id`, `name`, `lname`, `uname`, `email`, `pass`) VALUES (NULL, '$name', '$lname', '$uname', '$email1', '$pass1')") or die (mysql_error());



}else{
  echo "Sorry, your password is not corrext.";
  exit();
}
}else{
  echo "Sorry!";
}

} // brace for submit conditional

$form = <<<EOT
<form action="register.php" method="POST">
First Name: <input type="text" name="name" /></br>
Last Name: <input type="text" name="lname" /></br>
Username: <input type="text" name="uname" /></br>
Email: <input type="text" name="email1" /></br>
Confirm Email: <input type="text" name="email2" /></br>
Password: <input type="password" name="pass1" /></br>
Confirm Password: <input type="password" name="pass2" /></br>
<input type="submit" value="Register" name="submit" />
</form>
EOT;
echo $form;

?>

好吧，我知道我试图混合mysql和MySQLI....

Answer 1

帮你...（太长，无法发表评论）

您的require（“config.php”）；应包含以下内容：

旁白：为您的主机使用正确的设置。

$link = mysqli_connect("localhost", "username", "mpassword", "database") or die($link);

$name = mysqli_real_escape_string($link, $_POST['name']);
$lname = mysqli_real_escape_string($link, $_POST['lname']);
$uname = mysqli_real_escape_string($link, $_POST['uname']);
$email1 = mysqli_real_escape_string($link, $email1);
$email2 = mysqli_real_escape_string($link, $email2);
$pass1 = mysqli_real_escape_string($link, $pass1);
$pass2 = mysqli_real_escape_string($link, $pass2);

mysqli_query($link, "INSERT INTO ...

$query = mysqli_query($link, "INSERT INTO ...

if(!$query){
   echo "Error: " . mysqli_error($link);
   }

• 我可以在PHP中混合MySQL API吗？
• 你不能。mysql_与mysqli_或PDO等不能混合在一起。从连接到查询必须使用相同的。

脚注。

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