来自google解析json的iOS地理编码数据

Question

我正在从谷歌地图上提取一些数据，但我似乎不能用它做任何事情。下面是我的代码：

- (void)connectionDidFinishLoading:(NSURLConnection *)theConnection  {

//do something with the data!
NSError *e = nil;
//parse the json data
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: receivedData options: NSJSONReadingMutableContainers error: &e];

//get the lat and long and put it into an array
locationData = [[NSMutableArray alloc] init];

NSLog(@"%@", [jsonArray objectAtIndex:0]);

}

- (void)connectionDidFinishLoading:(NSURLConnection *)theConnection  {

//do something with the data!
NSError *e = nil;
//parse the json data
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: receivedData options: NSJSONReadingMutableContainers error: &e];

//get the lat and long and put it into an array
locationData = [[NSMutableArray alloc] init];

for(NSDictionary* thisLocationDict in jsonArray) { 

    NSString* location = [thisLocationDict objectForKey:@"results"];
    [locationData addObject:location];
}
}

-[__NSCFString objectForKey:]: unrecognized selector sent to instance 0x798a270

http://maps.googleapis.com/maps/api/geocode/json?address=2900+Horizon+Drive+King+of+Prussia+,+PA&sensor=false

你知道我做错了什么吗？

Answer 1

与从google获得的数据的不同之处在于，它是按键分开的，比如results、geometome、formatted_address...

您应该这样做：

NSError *error;

NSString *lookUpString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?address=%@&components=country:AU&sensor=false", self.searchBar.text];

lookUpString = [lookUpString stringByReplacingOccurrencesOfString:@" " withString:@"+"];

NSData *jsonResponse = [NSData dataWithContentsOfURL:[NSURL URLWithString:lookUpString]];

NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:jsonResponse options:kNilOptions error:&error];

self.locationArray = [[jsonDict valueForKey:@"results"] valueForKey:@"formatted_address"];

int total = self.locationArray.count;
NSLog(@"locationArray count: %d", self.locationArray.count);

for (int i = 0; i < total; i++)
{
    NSString *statusString = [jsonDict valueForKey:@"status"];
    NSLog(@"JSON Response Status:%@", statusString);

    NSLog(@"Address: %@", [self.locationArray objectAtIndex:i]);

}