无法从另一个片段打开一个片段

Question

在我的Main2Activity中有5个片段(home、settings、newPost、notifications和profile）。

在HomeFragment中，我有一个RecycerView，其中包含许多post视图，每个post都包含一个“open”按钮，该按钮应该打开一个PostFragment。问题是，我只能在RecyclerViewAdapter类和populateItemRows（）方法中使用SetonClickListener，所以当我不能使用GetActivity()...

public class HomeFragment extends Fragment{

    private RecyclerView recyclerView;
    private RecyclerViewAdapter recyclerViewAdapter;
    private boolean isLoading = false;
    private ArrayList<String> rowsArrayList = new ArrayList<>();

    public View onCreateView(@NonNull LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        View root = inflater.inflate(R.layout.fragment_home, container, false);

        recyclerView = root.findViewById(R.id.recyclerView);
        initAdapter();
        initScrollListener();

        return root;
    }

    private void initAdapter() {
        recyclerViewAdapter = new RecyclerViewAdapter(getActivity(),2);
        recyclerView.setLayoutManager(new LinearLayoutManager(getContext()));
        recyclerView.setAdapter(recyclerViewAdapter);
    }

    private void initScrollListener() {
       ...
    }

    private void loadMore() {
        ...
    }
}

RecycerViewAdapter：

public class RecyclerViewAdapter extends RecyclerView.Adapter<RecyclerView.ViewHolder> {

    private final int VIEW_TYPE_ITEM = 0;
    private final int VIEW_TYPE_LOADING = 1;
    private ArrayList<Post> list = new ArrayList();
    private static final String TAG = RecyclerViewAdapter.class.getSimpleName();
    private String userId = FirebaseAuth.getInstance().getCurrentUser() != null ? FirebaseAuth.getInstance().getCurrentUser().getUid() : null;
    private FirebaseFirestore db = FirebaseFirestore.getInstance();
    private Context context;
    private User currentUser;
    private int type;

    public RecyclerViewAdapter(Context context, int type) {
        this.context = context;
        this.type = type;
        if (type == 0) {
            myPostsRetriever(context);
        } else if (type == 1) {
            appliedToPostsRetriever(context);
        } else if (type == 2) {
            homePostsRetriever(context);
        }
    }

    @NonNull
    @Override
    public RecyclerView.ViewHolder onCreateViewHolder(@NonNull ViewGroup parent, int viewType) {
        ...
    }

    @Override
    public void onBindViewHolder(@NonNull RecyclerView.ViewHolder viewHolder, int position) {
        if (viewHolder instanceof ItemViewHolder) {
            populateItemRows((ItemViewHolder) viewHolder, position);
        } else if (viewHolder instanceof LoadingViewHolder) {
            showLoadingView((LoadingViewHolder) viewHolder, position);
        }
    }

    private void populateItemRows(ItemViewHolder viewHolder, int position) {
...

        viewHolder.itemView.findViewById(R.id.seePostButton).setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

        Fragment newFragment = new PostFragment();
        FragmentTransaction transaction = getActivity().getSupportFragmentManager().beginTransaction();
        transaction.replace(R.id.mobile_navigation, newFragment);
        transaction.addToBackStack(null);
        transaction.commit();
            }
        });
    }

Answer 1

您需要来自构造的上下文对象。

FragmentTransaction fm = ((AppCompatActivity) context).getSupportFragmentManager().beginTransaction();
transaction.replace(R.id.mobile_navigation, newFragment);
transaction.addToBackStack(null);
transaction.commit();