添加值并插入setText

Question

你好，我正在创建一个游戏，它有分数，我需要使点被添加和更改setText.

我在转换时遇到了问题，因为我在字符串中获取文本值，对其求和会产生错误。

    TextView pvoce = (TextView) findViewById(R.id.pvoce);
        TextView papp = (TextView) findViewById(R.id.papp);

if (escolhaApp == "pedra" && escolhaUsuario == "tesoura" || escolhaApp == "papel" && escolhaUsuario == "pedra" || escolhaApp == "tesoura" && escolhaUsuario == "papel") {
            textoResultado.setText("    You Lose   ");
            String soma = 1;
            int totalapp = (soma + papp);
            String totalappString = Integer.toString(totalapp);
            papp.setText(totalappString);

        } else if (escolhaUsuario == "pedra" && escolhaApp == "tesoura" || escolhaUsuario == "papel" && escolhaApp == "pedra" || escolhaUsuario == "tesoura" && escolhaApp == "papel") {
            textoResultado.setText("   You Win   ");
            int soma = 1;
            int totalvoce = soma + pvoce;
            String totalvoceString = Integer.toString(totalvoce);
            pvoce.setText(totalvoceString);
        }

错误：不兼容的类型：int无法转换为String错误：不兼容的类型：String无法转换为int错误：二进制运算符的坏操作数类型'第一种类型：int第二种类型：TextView

Answer 1

嗯，您必须稍微修改一下java基础知识

        String soma = 1; // you have a problem here call it Problem 1 
        int totalapp = (soma + papp); //  because of Problem 1 you get part of  Problem 2  and because of  papp is a view object, not a value you get the second part  so you have to get it's valued first by getText() Method 



        String totalappString = Integer.toString(totalapp); // and Problem 3 here 
        papp.setText(totalappString);

问题一是分配问题字符串应介于“”

              String soma ="1"; 
or you can consider soma as int from the beginning.It depends on how you are solving the problem, let us just take care of the syntax errors and semantics are upon your logic.

问题二是转换问题，因为papp是一个包含String类型的视图，值应该由getText（）获取，然后转换为整数，然后用于求和

              int totalapp = (Integer.parseInt(soma) + 
              Integer.parseInt(papp.getText()));//note papp.getText() 

Answer 2

我不会对错误有太多的强调，因为它已经在前面的答案中涵盖了。但是在这里，您可以通过注释出您的代码行来找到正确的解决方案，这些代码行对问题的一些解释有问题，并在每行的正下方写下更正后的代码

TextView pvoce = (TextView) findViewById(R.id.pvoce);
TextView papp = (TextView) findViewById(R.id.papp);

if (escolhaApp == "pedra" && escolhaUsuario == "tesoura" || escolhaApp == "papel" && escolhaUsuario == "pedra" || escolhaApp == "tesoura" && escolhaUsuario == "papel") {
            textoResultado.setText("    You Lose   ");
            // String soma = 1; // wrong as java is statically typed language, you can't assign a int into a String 
            int soma = 1;

           //  int totalapp = (soma + papp); // papp is of TextView type, you need to get its text by getText(), convert it to String by .toString(), and then into int to make the integer addition valid
            int totalapp = soma + Integer.parseInt(papp.getText().toString());

            String totalappString = Integer.toString(totalapp);
            papp.setText(totalappString);

        } else if (escolhaUsuario == "pedra" && escolhaApp == "tesoura" || escolhaUsuario == "papel" && escolhaApp == "pedra" || escolhaUsuario == "tesoura" && escolhaApp == "papel") {
            textoResultado.setText("   You Win   ");
            int soma = 1;
           //  int totalvoce = soma + pvoce; // pvoce is of TextView type, you need to get its text by getText(), convert it to String by .toString(), and then into int to make the integer addition valid
            int totalvoce = soma + Integer.parseInt(pvoce.getText().toString());

            String totalvoceString = Integer.toString(totalvoce);
            pvoce.setText(totalvoceString);
        }

Answer 3

Java是一种静态类型语言，这意味着您不能将值分配给不兼容的类型（String soma=1；不是有效的分配）。此外，papp是TextView的一个实例，而不是int，因此不能执行int totalapp=（soma papp） 。

在将TextView文本添加到任何其他值之前，您必须将其强制到int，例如：

TextView papp = (TextView) findViewById(R.id.papp);

int soma = 1;
int pappInt = 0;
try {
    pappInt = Integer.parseInt(papp.getText().toString());
} catch (NumberFormatException nfe) {
    // Cannot parse papp.getText() as an Integer
}

int totalapp = (soma + pappInt);