图中的平衡副词

Question

public void recursiveDFS(NodeGraph node){
    System.out.print(node + " ");
    List<NodeGraph> children = node.getChildren();
    node.setVisited(true);
    for (int currentIndex = 0; currentIndex < children.size(); currentIndex++) {
        NodeGraph currentNode = children.get(currentIndex);
        if (currentNode != null && currentNode.getIsVisited() == false) {
            recursiveDFS(currentNode);
        }
    }
}

Answer 1

您可能应该区分叶节点（如yy9、yy5、yy21和yy27)和非叶节点（如and或）。

具有超过1个子节点的非叶节点应该用括号包装。应该能奏效。