在POST请求中使用改版发送JSON[副本]

Question

{"id":1,"nom":"Hydrogène","slug":"hydrogene"}

@POST("{TableName}/{ID}/update/0.0")
Call<String> cl_updateData(@Path("TableName") String TableName, @Path("ID") String ID);

public class ClientServiceGenerator{
private static OkHttpClient httpClient = new OkHttpClient();

public static <S> S createService(Class<S> serviceClass, String URL) {
    Retrofit.Builder builder =
            new Retrofit.Builder()
                    .baseUrl(URL)
                    .addConverterFactory(GsonConverterFactory.create());

    Retrofit retrofit = builder.client(httpClient).build();
    return retrofit.create(serviceClass);
}}

APIService client = ClientServiceGenerator.createService(APIService.class, "http://mysiteexample.com/api.php/");
    Call<String> call = client.cl_updateData("atomes", "1");
    call.enqueue(new Callback<String>() {
        @Override
        public void onResponse(Response<String> response, Retrofit retrofit) {
            if (response.code() == 200 && response.body() != null){
                Log.e("sd", "OK");
            }else{
                Log.e("Err", response.message()+" : "+response.raw().toString());
            }
        }

        @Override
        public void onFailure(Throwable t) {
            AlertDialog alertError = QuickToolsBox.simpleAlert(EditDataActivity.this, "updateFail", t.getMessage(), new DialogInterface.OnClickListener() {
                @Override
                public void onClick(DialogInterface dialog, int which) {
                    dialog.cancel();
                }
            });
            alertError.show();
        }
    });

如果你还需要什么，请告诉我，希望有人能帮助我。

EDIT第一次没有提到它，但我的JSON不会总是使用相同的键(id、nom、slug)。

Answer 1

首先，您需要创建一个对象来表示所需的json：

public class Data {
    int id;
    String nom;
    String slug;

    public Data(int id, String nom, String slug) {
        this.id = id;
        this.nom = nom;
        this.slug = slug;
    }
}

然后，修改您的服务，使其能够发送此对象：

@POST("{TableName}/{ID}/update/0.0")
Call<String> cl_updateData(@Path("TableName") String TableName, @Path("ID") String ID, @Body Data data);

最后，传递这个对象：

Call<String> call = client.cl_updateData("atomes", "1", new Data(1, "Hydrogène", "hydrogene"));

@POST("{TableName}/{ID}/update/0.0")
Call<String> cl_updateData(@Path("TableName") String TableName, @Path("ID") String ID, 
        @Body Object data);