复制Tkinter树视图

Question

我正尝试在另一个窗口中显示ttk树视图。唯一的选择似乎是遍历原始的树视图并相应地填充新的树视图。

然而，我似乎不能得到所有的（许多）子文件夹在正确的地方，所有的东西都是混淆的2D级别（即，我得到根文件夹和他们的子代正确，然后子文件夹似乎插入在随机的位置）。

    def getsubchildren(item=''):
        children = []
        for child in original_treeview.get_children(item):
            i = new_treeview.insert(item, 'end', text=original_treeview.item(child) 
                                   ['text'],values=original_treeview.item(child)['values'])
            children.append(i)

        for subchild in children: 
            getsubchildren(subchild)

Answer 1

在不知道项的深度的情况下，您需要检查项是否有子项。如果是这样，则需要函数在循环中调用自身。下面是一个可行的例子：

import tkinter as tk
from tkinter import ttk

root = tk.Tk()

maintree = ttk.Treeview(root)
maintree.pack()

first = maintree.insert("","end",text='first')
second= maintree.insert(first,"end",text='second')
third= maintree.insert(second,"end",text='third')
fourth= maintree.insert(third,"end",text='fourth')

st = maintree.insert("","end",text='1st')
nd= maintree.insert(st,"end",text='2nd')
rd= maintree.insert(nd,"end",text='3rd')
th= maintree.insert(rd,"end",text='4th')

top = tk.Toplevel(root)
subtree = ttk.Treeview(top)
subtree.pack()

def copy_item_tree(item,child):
    for child in maintree.get_children(child):
        item = subtree.insert(item,"end",
                              text=maintree.item(child)['text'])
        if maintree.get_children(child):
            copy_item_tree(item,child)
def copy_tree():
    for child in maintree.get_children():
        item = subtree.insert("","end",text=maintree.item(child)['text'])
        copy_item_tree(item,child)

button = tk.Button(root,text='Copy Tree', command=copy_tree)
button.pack(fill='x')
root.mainloop()