对于下面的代码，经过一定时间后，我将得到-ve值作为+ve整数输入的输出。谁能解释一下这背后的原因吗？

Question

class fibonacci
{
public static void main(String[] args)
{
int a = 0;
int b = 1;
int c = 0;
int num = 1;
System.out.println(a);
System.out.println(b);
while(num < 100)
{
 c = a+b;
 a = b;
 b = c;
 num = num+1;
System.out.println(c);
}
}
}

输出：0 1 1 2 3 5 8 13 21 34 89 144 233 377 610 987 1597 258 4 418 1 676 5 109 46 177 11 286 763 68 750 25 121 393 196 418 317 811 514 229 832 040 134 6269 2178309 3524578 5702887 9227465 14930352 24157817 39088169 63245986 102334155 165580141 267914296 433494437 701408733 1134903170 1836311903-1323752223 512559680#+VE值-811192543-298632863#-VE值

Answer 1

导入java.Math.BigInteger；

    class fibonacci

    {

        public static void main(String[] args)
        {

            BigInteger  a = new BigInteger("0");
            BigInteger  b = new BigInteger("1");
            BigInteger  c = new BigInteger("0");
            BigInteger  num = new BigInteger("1");
            BigInteger testValue = new BigInteger("100");
            System.out.println(a);
            System.out.println(b);
            while((num.compareTo(testValue)==-1))
            {
                c = a.add(b);
                a = b;
                b = c;
                num = num.add(BigInteger.valueOf(1));
                System.out.println(c);
            }
        }
    }