Mapstruct@Mapper的uses属性不起作用

Question

我的一个Mapstruct映射器没有使用另一个映射器与@mapper（uses=

我们的验证支持需要映射器将实体映射到DTO。一个ValidationSupportNeedEntity包含一个ActivityEntity属性，我正在尝试从该属性映射到一个ActivityDTO。

因此，问题在于嵌套对象，即ActivityEntity到Active。

以下是源代码：

从ValidationSupport NeedMapper.java：

@Mapper(uses = {LifecycleErrorMessagesMapper.class, ActivityMapper.class})
public interface ValidationSupportNeedMapper {

   ValidationSupportNeed toValidationSupportNeed(ValidationSupportNeedEntity source);

...

来自ActivityMapper.java：

@Component
public class ActivityMapper {

    public Activity toActivity(ActivityEntity activity) {
       //Implementation
    }

    public ActivityEntity toActivityEntity(Activity activity) {
        //Implementation
    }

}

来自ValidationSupportNeedEntity.java（实体）

public class ValidationSupportNeedEntity {

    private ActivityEntity activityEntity;

来自ValidationSupporteed.java（DTO）

public class ValidationSupportNeed implements AutoValidated {
      private Activity validationActivity;

但是，Mapstruct似乎忽略了在@Mapper注释上使用=属性，并继续生成自己的映射方法，如下所示：

   @Override
    public ValidationSupportNeed toValidationSupportNeed(ValidationSupportNeedEntity source) {
        if ( source == null ) {
            return null;
        }

        ValidationSupportNeed validationSupportNeed = new ValidationSupportNeed();

        validationSupportNeed.setValidationActivity( validationSupportNeedEntityToActivity( source ) );
    ...
  }

    protected Activity validationSupportNeedEntityToActivity(ValidationSupportNeedEntity validationSupportNeedEntity) {
        if ( validationSupportNeedEntity == null ) {
            return null;
        }

        Activity activity = new Activity();

        activity.setCode( validationSupportNeedEntity.getValidationActivityCode() );

        return activity;
    }

我错过了什么？有人能帮忙吗？

编辑：ActivityMapper未自动连接到ValidationSupportNeedMapper实现中。

Answer 1

添加映射注释解决了以下问题：

@Mapping(source = "activityEntity", target = "validationActivity")
ValidationSupportNeed toValidationSupportNeed(ValidationSupportNeedEntity source);

请注意，属性的名称是不同的。